use*_*028 7 python mocking smtplib
smtplib.SMTP.sendmail尝试在单元测试中模拟.修补调用。该sendmail方法似乎已成功模拟,我们可以将其查询为MagicMock,但sendmail 模拟的called和called_args属性未正确更新。看来我没有正确应用补丁。
这是我正在尝试的一个简化示例:
import unittest.mock
with unittest.mock.patch('smtplib.SMTP', autospec=True) as mock:
import smtplib
smtp = smtplib.SMTP('localhost')
smtp.sendmail('me', 'me', 'hello world\n')
mock.assert_called() # <--- this succeeds
mock.sendmail.assert_called() # <--- this fails
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此示例生成:
AssertionError: Expected 'sendmail' to have been called.
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如果我将补丁更改为smtp.SMTP.sendmail;例如:
with unittest.mock.patch('smtplib.SMTP.sendmail.', autospec=True) as mock:
...
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在这种情况下,我可以成功访问模拟的called_args和属性,但由于允许进行初始化,因此与主机建立了实际的 smtp 会话。这是单元测试,我不希望发生实际的网络。calledsmtplib.SMTP
小智 12
我今天遇到了同样的问题,忘记了我正在使用上下文,所以只需更改
mock.sendmail.assert_called()
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到
mock.return_value.__enter__.return_value.sendmail.assert_called()
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这看起来很混乱,但这是我的例子:
msg = EmailMessage()
msg['From'] = 'no@no.com'
msg['To'] = 'no@no.com'
msg['Subject'] = 'subject'
msg.set_content('content');
with patch('smtplib.SMTP', autospec=True) as mock_smtp:
misc.send_email(msg)
mock_smtp.assert_called()
context = mock_smtp.return_value.__enter__.return_value
context.ehlo.assert_called()
context.starttls.assert_called()
context.login.assert_called()
context.send_message.assert_called_with(msg)
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