使用 Swift 包管理器时在测试目标之间共享代码

Chr*_*nce 15 xcode swift swift-package-manager

当我使用 Swift 包管理器时,我需要在测试目标之间共享一些代码。为此,我有一个 .testTarget,我也将其命名为另一个 .testTarget 中的依赖项。

这是一个简单的例子:

// swift-tools-version:5.3
// The swift-tools-version declares the minimum version of Swift required to build this package.

import PackageDescription

let package = Package(
    name: "ExampleLib",
    products: [
        // Products define the executables and libraries a package produces, and make them visible to other packages.
        .library(
            name: "ExampleLib",
            targets: ["ExampleLib"]),
    ],
    dependencies: [
        // Dependencies declare other packages that this package depends on.
        // .package(url: /* package url */, from: "1.0.0"),
    ],
    targets: [
        // Targets are the basic building blocks of a package. A target can define a module or a test suite.
        // Targets can depend on other targets in this package, and on products in packages this package depends on.
        .target(
            name: "ExampleLib",
            dependencies: []),
        .testTarget(
            name: "Common",
            dependencies: ["ExampleLib"]),
        .testTarget(
            name: "ExampleLibTests",
            dependencies: ["Common"]),
            
    ]
)
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如果我尝试在 Xcode 中构建此包,则会收到以下错误:

Unable to resolve build file: XCBCore.BuildFile (The workspace has a reference to a missing target with GUID 'PACKAGE-TARGET:Common')
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但是,如果我从命令行 ( swift build) 构建或从命令行 ( swift test) 测试,我就会成功。

我正在使用 Xcode 12 beta 6,但也尝试过 Xcode 11.5(更改了 Package.swift 标头)并获得相同的结果。

以下是完整的 Swift 包示例: https://www.dropbox.com/s/h6ypvbfonnb2zyk/ExampleLib.zip ?dl=0

我真的很想在 Xcode 中使用它来构建 iOS。想法?

cwe*_*ger 13

我遇到了同样的问题,并通过定义一个目标(而不是测试目标)来解决它Common

我的Package.swift文件:

// ...
.target(name: "Common", dependencies: ["App"], path: "Tests/Common"),
.testTarget(name: "AppTests", dependencies: ["App", "Common"]),
.testTarget(name: "IntegrationTests", dependencies: ["App", "Common"])
// ...
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  • 这是一个很好的解决方案,除非您实际上需要使用 @testsble 导入来提升访问级别,这仅在 .testTarget() 内部可用。 (4认同)