错误：传递给 App\Repository\FooRepository::__construct() 的参数 1 必须是 Doctrine\Common\Persistence\ManagerRegistry 的实例

Question

更新到doctrine/doctrine-bundle 2.1.2我收到此错误后：

传递给 App\Repository\FooRepository::__construct() 的参数 1 必须是 Doctrine\Common\Persistence\ManagerRegistry 的实例，给出的 Doctrine\Bundle\DoctrineBundle\Registry 实例，在 ...

我的存储库如下所示：

namespace App\Repository;

use App\Entity\Foo;
use Doctrine\ORM\QueryBuilder;
use Doctrine\Bundle\DoctrineBundle\Repository\ServiceEntityRepository;
use Doctrine\Common\Persistence\ManagerRegistry;

class FooRepository extends ServiceEntityRepository
{
    public function __construct(ManagerRegistry $registry)
    {
        parent::__construct($registry, Foo::class);
    }
}

=> 请参阅下面我自己的答案。

Answer 1

只需将这use一行从

use Doctrine\Common\Persistence\ManagerRegistry;

到

use Doctrine\Persistence\ManagerRegistry;

文档：https : //symfony.com/doc/current/doctrine.html#querying-for-objects-the-repository