如何使bash脚本在新行上终止

Question

这是出于学习目的.我写了一个模拟打字的脚本.

用法是:

$ typewriter (insert some text here)

然后脚本将以随机的方式回显它,看起来像是在打字.很好,但问题是,如果输入包含分号(;)它会中断.

例如:

$ typewriter hello; world

我想这是一个简单的修复.我只是想不出来.

提前致谢!

码:

#!/bin/bash
#Displays input as if someone were typing it

RANGE=4
the_input=$*
if [ x$* = "x" ] || [ x$* = "xusage" ] || [ x$* = "xhelp" ] || [ x$* = "x--help" ];
then
        echo "Usage: typewriter <some text that you want to look like it's typed>"
        exit 1

fi
  while [ -n "$the_input" ]
  do
    number=$RANDOM
    let "number %= RANGE"
    printf "%c" "$the_input"
    sleep .$number
    the_input=${the_input#?}
  done
  printf "\n"

Answer 1

不是真的:;表示命令的结束.你必须用管道和输入/输出重定向(一个类似的问题|,<,>),有意义的符号.

你唯一的选择是将参数放在引号中.

typewriter "some; text<>| that should be displayed"