我正在尝试呈现显示来自网络摄像头的视频捕获的 html 页面。但面临错误:- 500 Server Error TypeError: TemplateResponse() missing 1 required positional argument: 'context'
。我在 Flask 中尝试过的相同代码,在那里工作正常。
from fastapi import FastAPI
import uvicorn
from fastapi import Depends, FastAPI
from fastapi import FastAPI, Request
from fastapi.responses import HTMLResponse
from fastapi.templating import Jinja2Templates
import cv2
app = FastAPI(debug=True)
templates = Jinja2Templates(directory="templates")
@app.get("/")
async def index():
return templates.TemplateResponse("index.html")
async def gen_frames(camera_id):
cap= cv2.VideoCapture(0)
while True:
# for cap in caps:
# # Capture frame-by-frame
success, frame = cap.read() # read the camera frame
if not success:
break
else:
ret, buffer = cv2.imencode('.jpg', frame)
frame = buffer.tobytes()
yield (b'--frame\r\n'b'Content-Type: image/jpeg\r\n\r\n' + frame + b'\r\n')
if __name__ == '__main__':
uvicorn.run(app, host="127.0.0.1",port=8000)
Run Code Online (Sandbox Code Playgroud)
我的 HTML 页面是:- index.html
<!doctype html>
<html lang="en">
<head>
<!-- Required meta tags -->
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<!-- Bootstrap CSS -->
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css"
integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
<title>Multiple Live Streaming</title>
</head>
<body>
<div class="container">
<div class="row">
<div class="col-lg-7">
<h3 class="mt-5">Multiple Live Streaming</h3>
<img src="{{ url_for('video_feed', id='0') }}" width="100%">
</div>
</div>
</div>
</body>
</html>
Run Code Online (Sandbox Code Playgroud)
任何人都可以帮忙。我在这做错了什么。?相同的代码在 Flask 中工作
当您使用模板时,您需要传递一个请求。
from fastapi import Request
@app.get("/")
async def index(request: Request):
return templates.TemplateResponse("index.html", {"request": request})
Run Code Online (Sandbox Code Playgroud)
因此,您还可以使用StreamingResponse作为另一条路径提供视频
from fastapi.responses import StreamingResponse
@app.get("/serve/{camera_id}", include_in_schema=False)
async def serve_video(camera_id: int):
return StreamingResponse(gen_frames(camera_id))
Run Code Online (Sandbox Code Playgroud)
然后使用 Ajax 或 Axios 等获取该响应。
归档时间: |
|
查看次数: |
1505 次 |
最近记录: |