如何从 python 的输出中删除大括号？

Question

我是 Python 新手，我最近 1 周前开始学习，但我被困在这里......任何帮助将不胜感激......

from tkinter import *
import tkinter as tk
import psycopg2

root = Tk()

def get_info(Employee_Name, Department, Education,Salary):
   con = psycopg2.connect(dbname = 'postgres',user = 'postgres',password = 'Gaurav@31',host = 'localhost',port = 5432)
   cur = con.cursor()
   query = ('''INSERT INTO Employee (Employee_name, Department, Education,Salary) VALUES (%s,%s,%s,%s);''' )
   cur.execute(query,(Employee_Name, Department, Education,Salary))
   print('Data inserted Successfully')
   con.commit()
   con.close()
   display_all()

def search(emp_id):
    con = psycopg2.connect(dbname = 'postgres',user = 'postgres',password = 'Gaurav@31',host = 'localhost',port = 5432)
    cur = con.cursor()
    query = ('''SELECT * FROM EMPLOYEE WHERE emp_id = %s;''' )
    cur.execute(query,(emp_id))
    row = cur.fetchone()
    display_search(row)
    con.commit()
    con.close()

def display_search(row):
    listbox = Listbox(frame, width =50 , height=1)
    listbox.grid(row = 9 , column =1)
    listbox.insert(END,row)

def display_all():
    con = psycopg2.connect(dbname = 'postgres',user = 'postgres',password = 'Gaurav@31',host = 'localhost',port = 5432)
    cur = con.cursor()
    query = ('''SELECT * FROM Employee;''' )
    cur.execute(query)
    row = cur.fetchall()

    listbox = Listbox(frame, width =50 , height=8)
    listbox.grid(row = 10 , column =1)

    for x in row:
        listbox.insert(END,x)

canvas = Canvas(root, height = 480, width = 900)
canvas.pack()

frame = Frame()
frame.config(background="Black")
frame.place(relx = 0, rely = 0, relwidth = 1, relheight = 1)

label = Label(frame,text = " Employee Database")
labelfont = ('times', 24, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont)
label.grid(row=0,column=1,sticky = N)


label = Label(frame, text = 'Employee Name : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =1, column = 0,sticky='w')
entry_name = Entry(frame,width = 30)
entry_name.grid(row = 1, column= 1)

label = Label(frame, text = 'Department : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =2, column = 0, sticky ='w')
dept_name = Entry(frame,width = 30)
dept_name.grid(row = 2, column= 1)

label = Label(frame, text = 'Education : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =3, column = 0,sticky ='w')
education = Entry(frame,width = 30)
education.grid(row = 3, column= 1)

label = Label(frame, text = 'Salary : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =4, column = 0, sticky ='w')
salary = Entry(frame,width = 30)
salary.grid(row = 4, column= 1)

button = Button(frame, text = 'Add Information', command=lambda:         get_info(entry_name.get(),dept_name.get(),education.get(),salary.get()))
buttonfont1 = ('times', 13, 'bold')
button.config(bg = 'Black',fg ='Yellow',font =buttonfont1)
button.grid(row = 5 , column= 1)

label = Label(frame, text = 'Search by Emp_id : ')
labelfont1 = ('times', 14, 'bold')
label.config(bg = 'Black',fg ='Yellow', font =labelfont1)
label.grid(row = 6, column = 0, sticky ='w')
id_search = Entry(frame,width = 30)
id_search.grid(row = 6, column= 1)

button = Button(frame, text = 'Search',command = lambda:     search(id_search.get()))
buttonfont1 = ('times', 13, 'bold')
button.config(bg = 'Black',fg ='Yellow',font =buttonfont1)
button.grid(row = 7 , column= 1)

display_all()

root.mainloop()

请找到随附的代码以及屏幕截图：

我将删除列表框中可见的大括号，并且我希望以表格形式打印它

Answer 1

您正在将列表或元组而不是字符串插入到列表框中。在传递给插入方法之前，您需要将每一行显式转换为字符串。否则，底层 tcl 解释器将在将值转换为字符串时尝试通过添加大括号或反斜杠来保留数据的类似列表的结构。

考虑这段代码：

query = ('''SELECT * FROM Employee;''' )
cur.execute(query)
row = cur.fetchall()

row列表的列表。对于 中的每一项row，您都有该行中每一列的值列表。

稍后，将每一行添加到列表框中，如下所示：

for x in row:
    listbox.insert(END,x)

如前所述，x是每列的数据列表。但是，listbox.insert需要一个字符串。由于它不是字符串，tkinter 会使用自己的逻辑将其转换为字符串，这可能会导致添加花括号。

为了避免这种情况，您应该在调用之前显式地将列表转换为字符串insert。最简单的方法是在每个元素之间添加空格：

listbox.insert(END, " ".join(x))

如果“x”包含字符串以外的内容，则需要先将它们转换为字符串。最终版本可能看起来像这样：

string_data = [str(data) for data in x]
listbox.insert(END, " ".join(string_data))