从地理编码器结果中获取城市？

Question

从地理编码器结果中获取不同的数组内容时遇到问题.

item.formatted_address有效,但不是item.address_components.locality？

geocoder.geocode( {'address': request.term }, function(results, status) {

        response($.map(results, function(item) {

        alert(item.formatted_address+" "+item.address_components.locality)
    }            
}); 

//返回的数组是;

 "results" : [
      {
         "address_components" : [
            {
               "long_name" : "London",
               "short_name" : "London",
               "types" : [ "locality", "political" ]
            } ],
          "formatted_address" : "Westminster, London, UK" // rest of array...

任何帮助赞赏!

DC

Answer 1

最终使用以下工作:

var arrAddress = item.address_components;
var itemRoute='';
var itemLocality='';
var itemCountry='';
var itemPc='';
var itemSnumber='';

// iterate through address_component array
$.each(arrAddress, function (i, address_component) {
    console.log('address_component:'+i);

    if (address_component.types[0] == "route"){
        console.log(i+": route:"+address_component.long_name);
        itemRoute = address_component.long_name;
    }

    if (address_component.types[0] == "locality"){
        console.log("town:"+address_component.long_name);
        itemLocality = address_component.long_name;
    }

    if (address_component.types[0] == "country"){ 
        console.log("country:"+address_component.long_name); 
        itemCountry = address_component.long_name;
    }

    if (address_component.types[0] == "postal_code_prefix"){ 
        console.log("pc:"+address_component.long_name);  
        itemPc = address_component.long_name;
    }

    if (address_component.types[0] == "street_number"){ 
        console.log("street_number:"+address_component.long_name);  
        itemSnumber = address_component.long_name;
    }
    //return false; // break the loop   
});

Answer 2

尝试了几个不同的请求:

MK107BX

英国克利夫兰公园新月

就像你说的,返回的数组大小不一致,但两个结果的Town似乎都在address_component项中,类型为["locality","political"].也许你可以用它作为指标？

编辑:使用jQuery获取locality对象,将其添加到您的响应函数:

var arrAddress = item.results[0].address_components;
// iterate through address_component array
$.each(arrAddress, function (i, address_component) {
    if (address_component.types[0] == "locality") // locality type
        console.log(address_component.long_name); // here's your town name
        return false; // break the loop
    });

Answer 3

我必须创建一个程序,当用户点击地图上的某个位置时,该程序将填写用户表单中的纬度,经度,城市,县和州字段.该页面可以在http://krcproject.groups.et.byu.net找到,是一个允许公众为数据库贡献的用户表单.我并不认为自己是专家,但效果很好.

<script type="text/javascript">
  function initialize() 
  {
    //set initial settings for the map here
    var mapOptions = 
    {
      //set center of map as center for the contiguous US
      center: new google.maps.LatLng(39.828, -98.5795),
      zoom: 4,
      mapTypeId: google.maps.MapTypeId.HYBRID
    };

    //load the map
    var map = new google.maps.Map(document.getElementById("map"), mapOptions);

    //This runs when the user clicks on the map
    google.maps.event.addListener(map, 'click', function(event)
    {
      //initialize geocoder
      var geocoder = new google.maps.Geocoder()

      //load coordinates into the user form
      main_form.latitude.value = event.latLng.lat();
      main_form.longitude.value = event.latLng.lng();

      //prepare latitude and longitude
      var latlng = new google.maps.LatLng(event.latLng.lat(), event.latLng.lng());

      //get address info such as city and state from lat and long
      geocoder.geocode({'latLng': latlng}, function(results, status) 
      {
        if (status == google.maps.GeocoderStatus.OK) 
        {
          //break down the three dimensional array into simpler arrays
          for (i = 0 ; i < results.length ; ++i)
          {
            var super_var1 = results[i].address_components;
            for (j = 0 ; j < super_var1.length ; ++j)
            {
              var super_var2 = super_var1[j].types;
              for (k = 0 ; k < super_var2.length ; ++k)
              {
                //find city
                if (super_var2[k] == "locality")
                {
                  //put the city name in the form
                  main_form.city.value = super_var1[j].long_name;
                }
                //find county
                if (super_var2[k] == "administrative_area_level_2")
                {
                  //put the county name in the form
                  main_form.county.value = super_var1[j].long_name;
                }
                //find State
                if (super_var2[k] == "administrative_area_level_1")
                {
                  //put the state abbreviation in the form
                  main_form.state.value = super_var1[j].short_name;
                }
              }
            }
          }
        }
      });
    });
  }
</script>

Answer 4

我假设你想要城市和州/省:

var map_center = map.getCenter();
reverseGeocode(map_center);


function reverseGeocode(latlng){
  geocoder.geocode({'latLng': latlng}, function(results, status) {
      if (status == google.maps.GeocoderStatus.OK) {
            var level_1;
            var level_2;
            for (var x = 0, length_1 = results.length; x < length_1; x++){
              for (var y = 0, length_2 = results[x].address_components.length; y < length_2; y++){
                  var type = results[x].address_components[y].types[0];
                    if ( type === "administrative_area_level_1") {
                      level_1 = results[x].address_components[y].long_name;
                      if (level_2) break;
                    } else if (type === "locality"){
                      level_2 = results[x].address_components[y].long_name;
                      if (level_1) break;
                    }
                }
            }
            updateAddress(level_2, level_1);
       } 
  });
}

function updateAddress(city, prov){
   // do what you want with the address here
}

不要尝试返回结果,因为您会发现它们是未定义的 - 这是异步服务的结果.您必须调用一个函数,例如updateAddress();

Answer 5

我创建了这个函数来获取地理编码器结果的主要信息：

const getDataFromGeoCoderResult = (geoCoderResponse) => {
  const geoCoderResponseHead = geoCoderResponse[0];
  const geoCoderData = geoCoderResponseHead.address_components;
  const isEmptyData = !geoCoderResponseHead || !geoCoderData;

  if (isEmptyData) return {};

  return geoCoderData.reduce((acc, { types, long_name: value }) => {
    const type = types[0];

    switch (type) {
      case 'route':
        return { ...acc, route: value };
      case 'locality':
        return { ...acc, locality: value };
      case 'country':
        return { ...acc, country: value };
      case 'postal_code_prefix':
        return { ...acc, postalCodePrefix: value };
      case 'street_number':
        return { ...acc, streetNumber: value };
      default:
        return acc;
    }
  }, {});
};

所以，你可以这样使用它：

const geoCoderResponse = await geocodeByAddress(value);
const geoCoderData = getDataFromGeoCoderResult(geoCoderResponse);

假设您要搜索Santiago Bernabéu Stadium，那么结果将是：

{
  country: 'Spain',
  locality: 'Madrid',
  route: 'Avenida de Concha Espina',
  streetNumber: '1',
}