字符向量到数据帧

joh*_*ohn 2 r dataframe

我有以下格式的数据。向量的第一个元素是指标题,向量的第二个到底部是指与标题相对应的值。我想将数据放入表格/结构化格式(或带有标题和值的数据框)中。

k <- c("Afv.dato : Type Termin lalt Betalt pa termin Terminsbelgb", "13-09-2019 opkrzvning 11-09-2019 4.067,11",
  "18-10-2019 indbetaling 4.067,00 11-09-2019 4.067,00", "11-12-2019 opkrzvning 11-12-2019 9.176,00" ,
  "18-12-2019 indbetaling 9.176,11 11-09-2019 0,11", "11-12-2019 9.176,00", "11-03-2020 opkreevning 11-03-2020 9.176,00", 
  "02-03-2020 indbetaling 9.176,00 11-03-2020 9.176,00", "11-06-2020 opkraevning 11-06-2020 9.176,00",
  "18-05-2020 indbetaling 9,176,00 11-06-2020 9.176,00"         
)
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所需输出(前 5 行的值(包括标题) 在此处输入图片说明

GKi*_*GKi 5

您可以尝试使用strcapture.

strcapture("(\\d+-\\d+-\\d+) *(\\D*) *(\\d+-\\d+-\\d+)* *([0-9.,]*) *(\\d+-\\d+-\\d+)* *([0-9.,]*)",
 k[-1], data.frame(Afv.dato=character(), Type=character(), Termin=character(),
 lalt=character(), "Betalt pa termin"=character(), Terminsbelgb=character()))
#    Afv.dato         Type     Termin     lalt Betalt.pa.termin Terminsbelgb
#1 13-09-2019  opkrzvning  11-09-2019 4.067,11                              
#2 18-10-2019 indbetaling             4.067,00       11-09-2019     4.067,00
#3 11-12-2019  opkrzvning  11-12-2019 9.176,00                              
#4 18-12-2019 indbetaling             9.176,11       11-09-2019         0,11
#5 11-12-2019                         9.176,00                              
#6 11-03-2020 opkreevning  11-03-2020 9.176,00                              
#7 02-03-2020 indbetaling             9.176,00       11-03-2020     9.176,00
#8 11-06-2020 opkraevning  11-06-2020 9.176,00                              
#9 18-05-2020 indbetaling             9,176,00       11-06-2020     9.176,00
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