从 timedelta 中提取分钟 - Python

Question

我有一个包含 timedelta 的列，我想创建一个额外的列，从 timedelta 列中提取小时和分钟。

df

time_delta          hour_minute
02:51:21.401000     2h:51min
03:10:32.401000     3h:10min
08:46:43.401000     08h:46min

这是我到目前为止所尝试过的：

df['rh'] = df.time_delta.apply(lambda x: round(pd.Timedelta(x).total_seconds() \
                          % 86400.0 / 3600.0) )

不幸的是，我不太确定如何提取不包含在内的会议记录。小时

Answer 1

用于Series.dt.components获取小时和分钟并连接在一起：

td = pd.to_timedelta(df.time_delta).dt.components
df['rh'] = (td.hours.astype(str).str.zfill(2) + 'h:' + 
            td.minutes.astype(str).str.zfill(2) + 'min')
print (df)
        time_delta hour_minute         rh
0  02:51:21.401000    2h:51min  02h:51min
1  03:10:32.401000    3h:10min  03h:10min
2  08:46:43.401000   08h:46min  08h:46min

如果可能的小时值更像 24 小时，还需要添加天数：

print (df)
        time_delta hour_minute
0  02:51:21.401000    2h:51min
1  03:10:32.401000    3h:10min
2  28:46:43.401000   28h:46min

td = pd.to_timedelta(df.time_delta).dt.components
print (td)
   days  hours  minutes  seconds  milliseconds  microseconds  nanoseconds
0     0      2       51       21           401             0            0
1     0      3       10       32           401             0            0
2     1      4       46       43           401             0            0

df['rh'] = ((td.days * 24 + td.hours).astype(str).str.zfill(2) + 'h:' + 
            td.minutes.astype(str).str.zfill(2) + 'min')
print (df)

        time_delta hour_minute         rh
0  02:51:21.401000    2h:51min  02h:51min
1  03:10:32.401000    3h:10min  03h:10min
2  28:46:43.401000   28h:46min  28h:46min