Oll*_*rds 711 java json jackson
在杰克逊的数据绑定的文档表明,杰克逊支持deserialising"所有支持类型的数组",但我想不通这个确切的语法.
对于单个对象,我会这样做:
//json input
{
"id" : "junk",
"stuff" : "things"
}
//Java
MyClass instance = objectMapper.readValue(json, MyClass.class);
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现在对于一个数组我想这样做:
//json input
[{
"id" : "junk",
"stuff" : "things"
},
{
"id" : "spam",
"stuff" : "eggs"
}]
//Java
List<MyClass> entries = ?
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有人知道是否有一个神奇的缺失命令?如果没有那么解决方案是什么?
Pro*_*uce 1524
首先创建一个映射器:
import com.fasterxml.jackson.databind.ObjectMapper;// in play 2.3
ObjectMapper mapper = new ObjectMapper();
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作为数组:
MyClass[] myObjects = mapper.readValue(json, MyClass[].class);
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如清单:
List<MyClass> myObjects = mapper.readValue(jsonInput, new TypeReference<List<MyClass>>(){});
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另一种指定List类型的方法:
List<MyClass> myObjects = mapper.readValue(jsonInput, mapper.getTypeFactory().constructCollectionType(List.class, MyClass.class));
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Mar*_*hym 170
List<MyClass> myObjects = Arrays.asList(mapper.readValue(json, MyClass[].class))
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这个解决方案对我来说似乎是最好的
小智 48
尝试这个
List<MyClass> list = mapper.readerForListOf(MyClass.class).readValue(json)
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Obi*_*Jha 30
对于通用实现:
public static <T> List<T> parseJsonArray(String json,
Class<T> classOnWhichArrayIsDefined)
throws IOException, ClassNotFoundException {
ObjectMapper mapper = new ObjectMapper();
Class<T[]> arrayClass = (Class<T[]>) Class.forName("[L" + classOnWhichArrayIsDefined.getName() + ";");
T[] objects = mapper.readValue(json, arrayClass);
return Arrays.asList(objects);
}
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Gre*_*g D 10
首先创建一个线程安全的ObjectReader实例.
ObjectMapper objectMapper = new ObjectMapper();
ObjectReader objectReader = objectMapper.reader().forType(new TypeReference<List<MyClass>>(){});
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然后使用它:
List<MyClass> result = objectReader.readValue(inputStream);
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我无法使用这个答案,因为我的 linter 不允许未经检查的强制转换。
这是您可以使用的替代方案。我觉得这实际上是一个更清洁的解决方案。
public <T> List<T> parseJsonArray(String json, Class<T> clazz) throws JsonProcessingException {
var tree = objectMapper.readTree(json);
var list = new ArrayList<T>();
for (JsonNode jsonNode : tree) {
list.add(objectMapper.treeToValue(jsonNode, clazz));
}
return list;
}
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小智 7
try {
ObjectMapper mapper = new ObjectMapper();
JsonFactory f = new JsonFactory();
List<User> lstUser = null;
JsonParser jp = f.createJsonParser(new File("C:\\maven\\user.json"));
TypeReference<List<User>> tRef = new TypeReference<List<User>>() {};
lstUser = mapper.readValue(jp, tRef);
for (User user : lstUser) {
System.out.println(user.toString());
}
} catch (JsonGenerationException e) {
e.printStackTrace();
} catch (JsonMappingException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
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使用 ArrayList,这些不同的语法都对我有用:
ArrayList<MyClass> arrayList = ...
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使用objectMapper.getTypeFactory().constructCollectionType
:
objectMapper.readValue(json, objectMapper.getTypeFactory().constructCollectionType(ArrayList.class, MyClass.class));
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使用new TypeReference
:
objectMapper.readValue(json, new TypeReference<ArrayList<MyClass>>(){});
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使用new ArrayList<>(Arrays.asList)
:
new ArrayList<>(Arrays.asList(objectMapper.readValue(json, MyClass[].class)));
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我不能说哪一个最好用,但我最终使用了最后一个:
ArrayList<MyClass> arrayList = new ArrayList<>(Arrays.asList(objectMapper.readValue(json, MyClass[].class)));
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这是一个实用程序,可以转换 json2object 或 Object2json,无论您的 pojo(实体 T)如何
import java.io.IOException;
import java.io.StringWriter;
import java.util.List;
import com.fasterxml.jackson.core.JsonGenerationException;
import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
/**
*
* @author TIAGO.MEDICI
*
*/
public class JsonUtils {
public static boolean isJSONValid(String jsonInString) {
try {
final ObjectMapper mapper = new ObjectMapper();
mapper.readTree(jsonInString);
return true;
} catch (IOException e) {
return false;
}
}
public static String serializeAsJsonString(Object object) throws JsonGenerationException, JsonMappingException, IOException {
ObjectMapper objMapper = new ObjectMapper();
objMapper.enable(SerializationFeature.INDENT_OUTPUT);
objMapper.disable(SerializationFeature.FAIL_ON_EMPTY_BEANS);
StringWriter sw = new StringWriter();
objMapper.writeValue(sw, object);
return sw.toString();
}
public static String serializeAsJsonString(Object object, boolean indent) throws JsonGenerationException, JsonMappingException, IOException {
ObjectMapper objMapper = new ObjectMapper();
if (indent == true) {
objMapper.enable(SerializationFeature.INDENT_OUTPUT);
objMapper.disable(SerializationFeature.FAIL_ON_EMPTY_BEANS);
}
StringWriter stringWriter = new StringWriter();
objMapper.writeValue(stringWriter, object);
return stringWriter.toString();
}
public static <T> T jsonStringToObject(String content, Class<T> clazz) throws JsonParseException, JsonMappingException, IOException {
T obj = null;
ObjectMapper objMapper = new ObjectMapper();
obj = objMapper.readValue(content, clazz);
return obj;
}
@SuppressWarnings("rawtypes")
public static <T> T jsonStringToObjectArray(String content) throws JsonParseException, JsonMappingException, IOException {
T obj = null;
ObjectMapper mapper = new ObjectMapper();
obj = mapper.readValue(content, new TypeReference<List>() {
});
return obj;
}
public static <T> T jsonStringToObjectArray(String content, Class<T> clazz) throws JsonParseException, JsonMappingException, IOException {
T obj = null;
ObjectMapper mapper = new ObjectMapper();
mapper = new ObjectMapper().configure(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY, true);
obj = mapper.readValue(content, mapper.getTypeFactory().constructCollectionType(List.class, clazz));
return obj;
}
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