触摸后UIButton保持反向增加

Question

我创建了一组相同的自定义类型的对象.所有对象都具有方法showDeleteButton了hideDeleteButton.我发现当我隐藏删除按钮(删除它)按钮时,按下了retainCounter == 2.

这里的代码:

-(void)showDeleteButton {
if(!isDeleteButtonLoaded) { // Check that method was't triggered twice
    UIButton *aDeleteButton = [[UIButton alloc] initWithFrame:CGRectMake(-3, -7, 30, 29)]; // RC == 1
    [aDeleteButton setImage:[UIImage imageNamed:@"close_button.png"] forState:UIControlStateNormal];
    [self addSubview:aDeleteButton]; // RC == 2
    [aDeleteButton addTarget:self action:@selector(deleteButtonPressed:) forControlEvents:UIControlEventTouchUpInside];
    deleteButton = aDeleteButton;
    [aDeleteButton release]; // RC == 1
    isDeleteButtonLoaded = YES;
    NSLog(@"delete button retain count (created): %d", [deleteButton retainCount]);
    [self setNeedsDisplay];
}

}

-(void)deleteButtonPressed:(id)sender {
[delegate deleteImageAtPath:self.imageFullPath];

}

-(void)hideDeleteButton {
if(isDeleteButtonLoaded) {
    NSLog(@"delete button retain count (before): %d", [deleteButton retainCount]); // RC == 1
    [deleteButton removeFromSuperview]; // RC == 0
    deleteButton = nil;
    isDeleteButtonLoaded = NO;
    [self setNeedsDisplay];
}

}

所以对于按下按钮NSLog的第二种方法显示RC == 2!有任何想法吗？我100%确定无法从类外部访问deleteButton.

Answer 1

请勿查看RETAINCOUNT

啊哈

就任何理智的人而言,retainCount毫无意义,只要你遵守记忆规则,事情就会好起来.