Nis*_*ant 5 python sqlalchemy pyodbc
我们在 Python 2 + mxODBC 中工作的查询之一在 Python 3 + pyodbc 中不起作用;它会引发如下错误:Maximum number of parameters in the sql query is 2100.whileconnecting to SQL Server. 由于两个打印的查询都有 3000 个参数,我认为它在两种环境中都应该失败,但显然这里的情况似乎并非如此。在Python 2环境中,MSODBC 11或MSODBC 17都可以工作,所以我立即排除了与驱动程序相关的问题。
所以我的问题是:
list,因为参数列表将与 的长度成比例list?我觉得它看起来有点奇怪;我更愿意将它们连接list成一个,string因为数据库不理解list数据类型。脚注:我看到很多建议对数据进行分块的答案,但由于1 和 2,我想知道我是否首先做了正确的事情。
(由于它似乎与 pyodbc 有关,因此我在官方存储库中提出了内部问题。)
import sqlalchemy
import sqlalchemy.orm
from sqlalchemy import MetaData, Table
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm.session import Session
Base = declarative_base()
create_tables = """
CREATE TABLE products(
idn NUMERIC(8) PRIMARY KEY
);
"""
check_tables = """
SELECT * FROM products;
"""
insert_values = """
INSERT INTO products
(idn)
values
(1),
(2);
"""
delete_tables = """
DROP TABLE products;
"""
engine = sqlalchemy.create_engine('mssql+pyodbc://user:password@dsn')
connection = engine.connect()
cursor = engine.raw_connection().cursor()
Session = sqlalchemy.orm.sessionmaker(bind=connection)
session = Session()
session.execute(create_tables)
metadata = MetaData(connection)
class Products(Base):
__table__ = Table('products', metadata, autoload=True)
try:
session.execute(check_tables)
session.execute(insert_values)
session.commit()
query = session.query(Products).filter(
Products.idn.in_(list(range(0, 3000)))
)
query.all()
f = open("query.sql", "w")
f.write(str(query))
f.close()
finally:
session.execute(delete_tables)
session.commit()
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当您执行简单的.in_(list_of_values)SQLAlchemy 时,会呈现以下 SQL ...
SELECT team.prov AS team_prov, team.city AS team_city
FROM team
WHERE team.prov IN (?, ?)
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...其中 IN 子句中的每个值都指定为单独的参数值。pyodbc 将其发送到 SQL Server 作为...
exec sp_prepexec @p1 output,N'@P1 nvarchar(4),@P2 nvarchar(4)',N'SELECT team.prov AS team_prov, team.city AS team_city, team.team_name AS team_team_name
FROM team
WHERE team.prov IN (@P1, @P2)',N'AB',N'ON'
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...所以如果您的列表很长,您就会达到 2100 个参数的限制。据推测,mxODBC 在将参数值发送到 SQL Server 之前插入了内联参数值,例如,
SELECT team.prov AS team_prov, team.city AS team_city
FROM team
WHERE team.prov IN ('AB', 'ON')
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您可以让 SQLAlchemy 为您完成此操作
provinces = ["AB", "ON"]
stmt = (
session.query(Team)
.filter(
Team.prov.in_(sa.bindparam("p1", expanding=True, literal_execute=True))
)
.statement
)
result = list(session.query(Team).params(p1=provinces).from_statement(stmt))
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