kru*_*i21 5 dart dart-pub flutter
这是我的时间戳=“2020-05-29T17:43:39.622832+05:30”。我如何将它传递给函数 readTimeStamp (它会给我不是 int 类型的错误)?
date = DateTime.parse(bookDetails.timestamp);
print(readTimestamp(date));
String readTimestamp(int timestamp) {
var now = DateTime.now();
var date = DateTime.fromMillisecondsSinceEpoch(timestamp * 1000);
var diff = now.difference(date);
String time = '';
if (diff.inSeconds <= 0 ||
diff.inSeconds > 0 && diff.inMinutes == 0 ||
diff.inMinutes > 0 && diff.inHours == 0 ||
diff.inHours > 0 && diff.inDays == 0) {
} else if (diff.inDays > 0 && diff.inDays < 7) {
if (diff.inDays == 1) {
time = diff.inDays.toString() + ' DAY AGO';
} else {
time = diff.inDays.toString() + ' DAYS AGO';
}
} else {
if (diff.inDays == 7) {
time = (diff.inDays / 7).floor().toString() + ' WEEK AGO';
} else {
time = (diff.inDays / 7).floor().toString() + ' WEEKS AGO';
}
}
return time;
}
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这是我返回 3 天前的值的函数。
DateTime.parse返回一个DateTime. readTimestamp似乎期望自纪元以来的秒数,因此您只需使用DateTime.millisecondsSinceEpoch毫秒并将其转换为秒:
print(readTimestamp(date.millisecondsSinceEpoch ~/ 1000));
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就我个人而言,如果您控制该readTimestamp函数,我会将其不明确的timestamp参数重命名为secondsSinceEpoch,以明确它的期望。更好的方法是将其参数更改为DateTime直接采用 a,而不是进行不必要的DateTime<=> 毫秒 <=> 秒转换。