在 ConfigParser 解析的请求模块上使用 URL 时，InvalidSchema("未找到 {!r}".format(url)) 的 URL

Question

我在配置文件中有一个 URL，我使用 ConfigParser 解析该 URL 以获取请求

配置文件

[default]
root_url ='https://reqres.in/api/users?page=2'

FetchFeeds.py

import requests
from configparser import ConfigParser
import os
import requests


config = ConfigParser()
config.read(os.path.join(os.path.dirname(__file__), '../Config', 'config.ini'))
rootUrl = (config['default']['root_url'])
print(rootUrl)
response = requests.get(rootUrl)

即使 URL 打印正确'https://reqres.in/api/users?page=2'，但我在请求模块上收到以下错误

Traceback (most recent call last):
  File "C:/Users/sam/PycharmProjects/testProject/GET_Request/FetchFeeds.py", line 11, in <module>
    response = requests.get(rootUrl)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\api.py", line 76, in get
    return request('get', url, params=params, **kwargs)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\api.py", line 61, in request
    return session.request(method=method, url=url, **kwargs)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\sessions.py", line 530, in request
    resp = self.send(prep, **send_kwargs)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\sessions.py", line 637, in send
    adapter = self.get_adapter(url=request.url)
  File "C:\Users\sam\PycharmProjects\testProject\venv\lib\site-packages\requests\sessions.py", line 730, in get_adapter
    raise InvalidSchema("No connection adapters were found for {!r}".format(url))
requests.exceptions.InvalidSchema: No connection adapters were found for "'https://reqres.in/api/users?page=2'"

Process finished with exit code 1

请注意我仔细检查了没有空格

Answer 1

主要问题是它试图找到一个'url.com'不存在的 URL（正确的是url.com），因此解决方案是不要在 config.ini 文件中添加撇号：

[default]
root_url = https://reqres.in/api/users?page=2

还要考虑一下是否在代码中而不是在配置文件中配置参数，并使用以下代码：

requests.get(config['default']['root_url'], params={'page': 2})