Dim*_*iev 0 aws-lambda aws-step-functions
我想根据上一步的结果动态选择 AWS Lambda 工作人员。类似的东西{"Resource": "$.worker_arn"}。
"RunWorkers": {
"Type": "Map",
"MaxConcurrency": 0,
"InputPath": "$.output",
"ResultPath": "$.raw_result",
"Iterator": {
"StartAt": "CallWorkerLambda",
"States": {
"CallWorkerLambda": {
"Type": "Task",
"Resource": "$$.worker_arn",
"End": true
}
}
},
"Next": "Aggregate"
},
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上一步的输入预期如下:
[{"worker_arn":..., "output":1}, {"worker_arn":..., "output":1}, ...],其中worker_arn所有工人都相同。
当我编写这样的管道时,linter 抱怨它需要一个 ARN。
有没有比将我的工人 lambda 包装到另一个 lambda 更好的选择?
使用"Resource": "arm:aws:states:::lambda:invoke"您可以在运行时使用路径设置"FunctionName"字段"Parameters"。
{
"StartAt":"CallLambda",
"States":{
"CallLambda":{
"Type":"Task",
"Resource": "arn:aws:states:::lambda:invoke",
"Parameters":{
"FunctionName.$":"$.MyFunction",
"Payload.$": "$"
},
"End":true
}
}
}
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https://docs.aws.amazon.com/step-functions/latest/dg/connect-lambda.html
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