Python：如何获取文件路径的最后n个元素

Question

假设我有这样的路径：

/folderA/folderB/folderC/item1
/folderA/folderB/folderX/item2
/folderA/folderB/folderF/item1
/folderA/folderB/folderQ/item5

如何获取文件路径的最后两个元素？

folderC/item1
folderX/item2
folderF/item1
folderQ/item5

我知道我可以 git 目录或文件

>>> os.path.basename('/folderA/folderB/folderC/item1')
>>> item1


>>> os.path.dirname('/folderA/folderB/folderC/item1')
>>> /folderA/folderB/folderC/

Answer 1

from pathlib import Path
path = r"/folderA/folderB/folderC/item1"
Path(*Path(path).parts[-2:])

输出：

PosixPath('folderC/item1')

注意：如果您愿意，可以将PosixPath对象转换为 str

Answer 2

import os
path = r"/folderA/folderB/folderC/item1"

对于 Windows：

os.sep.join(path.rsplit(r"/")[-2:])

独立于操作系统：

os.sep.join(os.path.normpath(path).split(os.sep)[-2:])