PHP脚本在网页上搜索单词

SJS*_*SJS 3 html php parsing

如果有人在网站http://www.stutteringjohnsmith.com上包含单词“ standup”,则可以告诉我如何更改以下PHP脚本以说为“找到”,如果没有,则如何显示为“找不到”

<?php
$data = file_get_contents('http://www.stutteringjohnsmmith.com/#/0');
$regex = '/Page 1 of (.+?) results/';
preg_match($regex,$data,$match);
var_dump($match);
echo $match[1];
?>
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dyn*_*mic 5

<?php
$data = file_get_contents('http://www.stutteringjohnsmmith.com/#/0');
$regex = '/standup/';    //<----
preg_match($regex,$data,$match);
var_dump($match);
echo $match[1];
?>
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大声笑?