读取 R 中的日志文件，以便每一行都以时间戳开头

Question

我有一个包含此类数据的日志文件：

2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ResourceLoaderHelper: 10 - Trying to upload data
2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ResourceLoaderHelper: 66 - Trying to upload data
2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ValidationXmlParser: 127 - No META-Only annotation
2020-07-28 14:48:00 (pool-2-thread-1id) DEBUG MessageWriter: 55 - Send message ErrorOutputMessage(super=NotificationOutputMessage(super=OutputMessage(type=null, messageId=116345, reqId=af24112))), error=ErrorOutputMessage.Error(code=400, text={
  "errors": [
    "Message type error"
  ]
})) to exchange FOS 
2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ValidatorFactoryImpl: 578 - Scoped message interpolator.

我尝试以这种方式读取该文件：

data <- readr::read_lines(file = "log_data.log", progress = FALSE)
log_df <- setDT(tibble::enframe(data, name = NULL))

但是这个数据框看起来像这样：

              value
1   2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ResourceLoaderHelper: 10 - Trying to upload data
 
2   2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ResourceLoaderHelper: 66 - Trying to upload data
3   2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ValidationXmlParser: 127 - No META-Only annotation
4   2020-07-28 14:48:00 (pool-2-thread-1id) DEBUG MessageWriter: 55 - Send message ErrorOutputMessage(super=NotificationOutputMessage(super=OutputMessage(type=null, messageId=116345, reqId=af24112))), error=ErrorOutputMessage.Error(code=400, text={
5     "errors": [
6         "Message type error"
7     ]
8   })) to exchange FOS 
9   2020-07-28 10:07:01 (pool-3-thread-5id) DEBUG ValidatorFactoryImpl: 578 - Scoped message interpolator.

所以当你看到第 4 行被分成几行时，认为它是一排。我怎么能读取这个日志文件，所以它明白每一行必须以时间戳开头？我应该以某种方式使用正则表达式吗？