如何使用Powershell向Twitter发布推文？

Question

有没有人使用过以下代码？如何发布推文？我知道我必须使用" $req.Context.RawUri = [Uri]'http://api.twitter.com/version/statuses/update.xml"但我无法得到" $res = [xml][DevDefined.OAuth.Consumer.ConsumerRequestExtensions]::ReadBody($req)".

Add-Type -Path C:\OAuthDevDefined\DevDefined.OAuth.dll

$cons = New-Object devdefined.oauth.consumer.oauthconsumercontext

$cons.ConsumerKey = 'key'

$cons.ConsumerSecret = 'key'

$cons.SignatureMethod = [devdefined.oauth.framework.signaturemethod]::HmacSha1

$session = new-object DevDefined.OAuth.Consumer.OAuthSession $cons, $null, $null, $null

$accessToken = new-object DevDefined.OAuth.Framework.TokenBase

$at = import-cliXml C:\temp\myTwitterAccessToken.clixml

$accessToken.ConsumerKey, $accessToken.Realm, $accessToken.Token, $accessToken.TokenSecret = `
  $at.ConsumerKey, $at.Realm, $at.Token, $at.TokenSecret

$req = $session.Request($accessToken)

$req.Context.RequestMethod = 'GET'

$req.Context.RawUri = [Uri]'http://api.twitter.com/1/statuses/friends_timeline.xml?count=5'

$res = [xml][DevDefined.OAuth.Consumer.ConsumerRequestExtensions]::ReadBody($req)

$res.statuses.status | % { $_.user.Name }

Answer 1

我也使用DevDefined的OAuth.我的功能看起来像这样:

function Post-Twitter {
    param(
        [Parameter(Mandatory=$true)][string]$url
    )
    if (!$script:accessToken) {
        throw 'token is not initialized'
    }

  try {
    $cons = New-Object devdefined.oauth.consumer.oauthconsumercontext
    $cons.ConsumerKey = $consumerKey
    $cons.ConsumerSecret = $consumerSecret
    $cons.SignatureMethod = [devdefined.oauth.framework.signaturemethod]::HmacSha1
    $session = new-object DevDefined.OAuth.Consumer.OAuthSession `
      $cons,
      "http://twitter.com/oauth/request_token",
      "http://twitter.com/oauth/authorize",
      "http://twitter.com/oauth/access_token"
    $token = Get-AccessToken 
    $req = $session.Request($token)
    $req.Context.RequestMethod = 'POST'
    $req.Context.RawUri = new-object Uri $url
    [DevDefined.OAuth.Consumer.ConsumerRequestExtensions]::ReadBody($req)
    } catch {
    Write-Warning "Exception: $_"
    $null
  }
}

为简单起见,我在查询字符串中传递状态:

add-type -assembly System.Web
$status = [system.Web.Httputility]::UrlEncode('some tweet')
Post-Twitter "http://api.twitter.com/1/statuses/update.xml?status=$status"

看来你知道消费者的密钥/秘密和令牌的东西,所以我会留下它而不作进一步的解释.