Sat*_*yaV 8 python arrays list
我有一个数组,给定一组中的项目数和组数,我需要在循环中循环打印该数组。数组-[1,2,3,4,5,6] 组- 4 次迭代- 7
输出应该是:
['1', '2', '3', '4']
['5', '6', '1', '2']
['3', '4', '5', '6']
['1', '2', '3', '4']
['5', '6', '1', '2']
['3', '4', '5', '6']
['1', '2', '3', '4']
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Pau*_*zer 11
np.resize 这里很方便:
np.resize([1,2,3,4,5,6],(7,4))
# array([[1, 2, 3, 4],
# [5, 6, 1, 2],
# [3, 4, 5, 6],
# [1, 2, 3, 4],
# [5, 6, 1, 2],
# [3, 4, 5, 6],
# [1, 2, 3, 4]])
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这是一种方法。我创建了一个由输入数组组成的更长的列表两次,所以是这样的:
[1,2,3,4,5,6,1,2,3,4,5,6]
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然后将其从起始索引切片i到i+N(N是组的大小,在本例中为 4)。
a = [1,2,3,4,5,6]
N = 4 # Number of elements in a group
aa = a+a # create a list composed of the array 'a' twice
i = 0 # starting index
for loop in range(7):
# extract the elements from the doublelist
print(aa[i:i+N])
# The next starting point has to be within the range of array 'a'
i = (i+N)%len(a)
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输出:
[1, 2, 3, 4]
[5, 6, 1, 2]
[3, 4, 5, 6]
[1, 2, 3, 4]
[5, 6, 1, 2]
[3, 4, 5, 6]
[1, 2, 3, 4]
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您可以尝试以下使用itertools.cycle:
import itertools
t = [1, 2, 3, 4, 5, 6]
number_of_elms_in_a_group = 4
iteration_number = 7
groups = []
group = []
for i, x in enumerate(itertools.cycle(t)):
if len(groups) >= iteration_number:
break
if i % number_of_elms_in_a_group == 0 and i != 0:
groups.append(group)
group = []
group.append(x)
# At this point,
# groups == [[1, 2, 3, 4], [5, 6, 1, 2], [3, 4, 5, 6],
# [1, 2, 3, 4], [5, 6, 1, 2], [3, 4, 5, 6],
# [1, 2, 3, 4]]
for group in groups:
print(group)
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哪个打印
[1, 2, 3, 4]
[5, 6, 1, 2]
[3, 4, 5, 6]
[1, 2, 3, 4]
[5, 6, 1, 2]
[3, 4, 5, 6]
[1, 2, 3, 4]
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一种解决方案是itertools.cycle与itertools.slice.
from itertools import cycle, islice
def format_print(iterable, group_size, iterations):
iterable = cycle(iterable)
for _ in range(iterations):
print(list(islice(iterable, 0, group_size)))
format_print(range(1, 7), 4, 7)
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输出:
[1, 2, 3, 4]
[5, 6, 1, 2]
[3, 4, 5, 6]
[1, 2, 3, 4]
[5, 6, 1, 2]
[3, 4, 5, 6]
[1, 2, 3, 4]
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如果需要打印字符串列表,cycle(iterable)可以替换为cycle(map(str, iterable)).
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