F#尾调用优化2个递归调用?

Der*_*aly 11 recursion f# functional-programming tail-recursion tail-call-optimization

当我写这个函数时,我知道我不会得到尾调优化.我仍然没有想出一个处理这个的好方法,并希望别人可以提供建议.

我有一棵树:

type Heap<'a> =
| E
| T of int * 'a * Heap<'a> * Heap<'a> 
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我想要计算其中有多少个节点:

let count h =
    let rec count' h acc =
        match h with 
        | E -> 0 + acc
        | T(_, value, leftChild, rightChild) ->
            let acc = 1 + acc
            (count' leftChild acc) + (count' rightChild acc)

    count' h 0
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由于添加了子节点的计数,因此未进行优化.如果树有100万个节点,任何想法如何制作这样的东西?

谢谢,德里克


这是使用CPS实现计数.它仍然吹响了堆栈.

let count h =
    let rec count' h acc cont =
        match h with
        | E -> cont (1 + acc)
        | T(_,_,left,right) ->
            let f = (fun lc -> count' right lc cont)
            count' left acc f

    count' h 0 (fun (x: int) -> x)
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也许我可以想出一些方法将树分割成足够的碎片,我可以计算而不会烧掉堆叠?

有人询问生成树的代码.它在下面.

member this.ParallelHeaps threads =
    let rand = new Random()
    let maxVal = 1000000

    let rec heaper i h =
        if i < 1 then
            h
        else
            let heap = LeftistHeap.insert (rand.Next(100,2 * maxVal)) h
            heaper (i - 1) heap

    let heaps = Array.create threads E
    printfn "Creating heap of %d elements, with %d threads" maxVal threads
    let startTime = DateTime.Now
    seq { for i in 0 .. (threads - 1) ->
          async { Array.set heaps i (heaper (maxVal / threads) E) }}
    |> Async.Parallel
    |> Async.RunSynchronously 
    |> ignore

    printfn "Creating %d sub-heaps took %f milliseconds" threads (DateTime.Now - startTime).TotalMilliseconds
    let startTime = DateTime.Now

    Array.length heaps |> should_ equal threads <| "The size of the heaps array should match the number of threads to process the heaps"

    let rec reMerge i h =
        match i with 
        | -1 -> h
        | _  -> 
            printfn "heap[%d].count = %d" i (LeftistHeap.count heaps.[i])
            LeftistHeap.merge heaps.[i] (reMerge (i-1) h)

    let heap = reMerge (threads-1) E
    printfn "Merging %d heaps took %f milliseconds" threads (DateTime.Now - startTime).TotalMilliseconds
    printfn "heap min: %d" (LeftistHeap.findMin heap)

    LeftistHeap.count heap |> should_ equal maxVal <| "The count of the reMerged heap should equal maxVal"
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Joh*_*Joh 10

您可以使用延续传递样式(CPS)来解决该问题.请参阅递归递归 -由Matthew Podwysocki 继续传递.

let tree_size_cont tree = 
  let rec size_acc tree acc cont = 
    match tree with 
    | Leaf _ -> cont (1 + acc) 
    | Node(_, left, right) -> 
         size_acc left acc (fun left_size -> 
         size_acc right left_size cont) 

  size_acc tree 0 (fun x -> x)
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另请注意,在Debug版本中,禁用尾部调用优化.如果您不想在发布模式下运行,可以在Visual Studio中的项目属性中启用优化.

  • 通常,是的,但这被认为是好的.但是,对于大多数语言,堆栈具有静态大小(在加载或编译时设置),据我所知,包括F#,因此它会比使用CPS创建内存不足情况更快地创建堆栈溢出.一般来说,许多计算问题需要无限制的数据结构用于任意输入,无论你是通过显式数据结构还是"隐式"结构,如不断增长的延续都是随意的:数据需要去某处. (2认同)

Jon*_*rop 5

CPS是一个很好的通用解决方案,但您可能还想考虑显式使用堆栈,因为它会更快并且可以说更简单:

let count heap =
  let stack = System.Collections.Generic.Stack[heap]
  let mutable n = 0
  while stack.Count > 0 do
    match stack.Pop() with
    | E -> ()
    | T(_, _, heap1, heap2) ->
        n <- n + 1
        stack.Push heap1
        stack.Push heap2
  n
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