vas*_*111 5 python plot python-3.x plotly
这是代码:
import plotly.graph_objects as go
fig = go.Figure()
fig.add_trace(go.Bar(
name='Group 1',
x=['Var 1', 'Var 2', 'Var 3'], y=[3, 6, 4],
error_y=dict(type='data', array=[1, 0.5, 1.5]),
width=0.15
))
fig.add_trace(go.Bar(
name='Group 2',
x=['Var 1', 'Var 2', 'Var 3'], y=[4, 7, 3],
error_y=dict(type='data', array=[0.5, 1, 2]),
width=0.15
))
fig.update_layout(barmode='group',
title=dict(
text = "Some <br> title <br> here",
x = 0.5,
y = 0.95,
xanchor = 'center',
yanchor = 'top',
#pad = dict(
# t = 0
# ),
font = dict(
#family='Courier New, monospace',
size = 40,
#color='#000000'
)
))
fig.show()
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这是输出:
问题:如何在不减小绘图标题字体大小的情况下正确对齐标题?
当然,这只是示例,实际情节会有所不同。问题的主要思想是找到正确调整大字体标题的解决方案。
调整边距并进行小幅调整y=0.95
应该可以解决问题:
import plotly.graph_objects as go
fig = go.Figure()
fig.add_trace(go.Bar(
name='Group 1',
x=['Var 1', 'Var 2', 'Var 3'], y=[3, 6, 4],
error_y=dict(type='data', array=[1, 0.5, 1.5]),
width=0.15
))
fig.add_trace(go.Bar(
name='Group 2',
x=['Var 1', 'Var 2', 'Var 3'], y=[4, 7, 3],
error_y=dict(type='data', array=[0.5, 1, 2]),
width=0.15
))
fig.update_layout(barmode='group',
title=dict(
text = "Some <br> title <br> here",
x = 0.5,
y = 0.90,
xanchor = 'center',
yanchor = 'top',
#pad = dict(
# t = 0
# ),
font = dict(
#family='Courier New, monospace',
size = 40,
#color='#000000'
)
))
fig.update_layout(margin=dict(l=50, r=50, t=200, b=50),paper_bgcolor="LightSteelBlue")
fig.show()
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