从列表中编辑嵌套字典中的值（python）

Question

对不起，如果有人问过，但我找不到正确的答案。我有 2 个列表：

list1 = [1, 2, 3, 5, 8]
list2 = [100, 200, 300, 400, 500]

和嵌套字典：

myDict = {
    1: {'first': None, 'second': None, 'third': None} ,
    2: {'first': None, 'second': None, 'third': None} ,
    3: {'first': None, 'second': None, 'third': None} ,
    5: {'first': None, 'second': None, 'third': None} ,
    8: {'first': None, 'second': None, 'third': None} ,
    }

如何根据键在 myDict 内的每个字典中插入值？ 预期输出：

myDict= {
    1: {'first': 100, 'second': None, 'third': None} ,
    2: {'first': 200, 'second': None, 'third': None} ,
    3: {'first': 300, 'second': None, 'third': None} ,
    5: {'first': 400, 'second': None, 'third': None} ,
    8: {'first': 500, 'second': None, 'third': None} ,
    }

我试过的：

for i in list1:
   for j in list2:
       myDict[i]['first'] = j
print(myDict)

我得到了什么（它用列表中的最后一项替换所有值）

{1: {'first': 500, 'second': None, 'third': None},
2: {'first': 500, 'second': None, 'third': None},
3: {'first': 500, 'second': None, 'third': None},
5: {'first': 500, 'second': None, 'third': None},
8: {'first': 500, 'second': None, 'third': None}
}

谢谢

Answer 1

你需要的是拉链

for i, j in zip(list1, list2):
   myDict[i]['first'] = j