如何使用多个参数过滤对象数组

Question

我希望能够通过多个参数过滤数据数组：

const data = [{
    userId: '7',
    id: '1',
    title: 'quo provident culpa',
    body: "a",
    completed: true
  },
  {
    userId: '7',
    id: '2',
    title: 'natus commodi et',
        body: "a",
    completed: true
  },
  {
    userId: '1',
    id: '3',
    title: 'voluptatem et reprehenderit',
    body: "c",
    completed: false
  }
];

const query = {
  title: 'l',
  body: 'a'
}

我试过这个：

const filterData = (data, query) => {
  return data.filter(rec => {
    return Object.keys(query)
      .find(key => rec[key] === query[key])
  })
}

console.log(filterData(data, query))

我的解决方案不太有效，因为它返回满足至少一个参数的任何对象。在上面的情况下，我得到了这个返回：

[{
  body: "a",
  completed: true,
  id: "1",
  title: "quo provident culpa",
  userId: "7"
}, {
  body: "a",
  completed: true,
  id: "2",
  title: "natus commodi et",
  userId: "7"
}]

但我真正想要的是通过部分匹配字符串只返回满足两个条件（title和body）的内容。像这样：

{
  userId: '7',
  id: '1',
  title: 'quo provident culpa',
  completed: true
}

我知道 find() 方法返回满足条件的第一个元素，但这是我能得到的最接近的元素，因为我想要它

Answer 1

您可以过滤Array#every所需的参数并仅使用String#includes.

const
    data = [{ userId: '7', id: '1', title: 'quo provident culpa', body: "a", completed: true }, { userId: '7', id: '2', title: 'natus commodi et',  body: "a", completed: true }, { userId: '1', id: '3', title: 'voluptatem et reprehenderit', body: "c", completed: false }],
    query = { title: 'l', body: 'a' },
    filterData = (data, query) => data.filter(rec => Object
        .entries(query)
        .every(([k, v]) => rec[k].toString().includes(v))
    );

console.log(filterData(data, query));