Flutter中发送补丁请求的方式

Question

端点：http ://127.0.0.1:8000 /users/current/ 用于更新当前登录的用户。需要更新这些字段：当我使用 POSTMAN 将数据作为 JSON 发送到端点时：

{
    "first_name": "Amir",
    "last_name": "",
    "profile": {
        "location": "Florida",
        "profession": "Not being useless",
    }
}

我应该如何在flutter中将其以http包形式发送？目前我通过以下方式发送：

Future<void> updateCurrentUserInformation(Teacher newTeacher) async {
    const String url = "http://10.0.2.2:8000/users/current/";
    await http.patch(
      url,
      body: {
        "first_name": newTeacher.first_name,
        "profile": "" //HOW DO I SHOULD SEND A MAP TO UPDATE LOCATION AND PROFESSION?
      },
      headers: {"Authorization": "JWT $authToken"},
    ).then((value) {
      print(authToken);
      print(value.body);
    });
  }

我应该如何发送地图来更新位置和职业？

更新：即使我将配置文件编码为 JSON 服务器返回：{"profile":["This field is required."]}

这是代码：

Future<void> updateCurrentUserInformation(Athlete newTeacher) async {
    const String url = "http://10.0.2.2:8000/users/current/";
    var profile = json.encode({
      "edu": newTeacher.education,
      "location": newTeacher.location,
      "profession": newTeacher.
      "image": "",
    });
    await http.patch(
      url,
      body: {
        "first_name": "amiramiramir",
        "profile": profile
      },
      headers: {"Authorization": "JWT $authToken"},
    ).then((value) {
      print(authToken);
      print(value.body);
    });
  }

服务器端收到的数据：

<QueryDict: {'first_name': ['amiramiramir'], 'profile': ['{"edu":"something","location":"somelocation","profession":"being useless"}']}>
 

Answer 1

您可以将地图转换为 JSON 字符串。使用json.encode(yourMap)。

import 'dart:convert';
Future<void> updateCurrentUserInformation(Teacher newTeacher) async {
    const String url = "http://10.0.2.2:8000/users/current/";
    await http.patch(
      url,
      body: {
        "first_name": newTeacher.first_name,
        "profile": json.encode(newTeacher.yourMap) //HOW DO I SHOULD SEND A MAP TO UPDATE LOCATION AND PROFESSION?
      },
      headers: {"Authorization": "JWT $authToken"},
    ).then((value) {
      print(authToken);
      print(value.body);
    });
  }