Python 子字符串 - 将第 n 个字符拆分到某个字符串的左侧

Question

我有以下示例字符串：

0015CB,0,0,01,006D,0016CF1,4,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00F4E7D,1,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0008184,8,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA704,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0014EC8,2,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FAEEA,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FADE9,5,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA5A5,3,000D

请您告诉我如何在每次迭代的左侧获得 9 个字符"000D"，因此第一个结果将是：

0016CF1,4

第二次提取将是：

00F4E7D,1

第三个是：

0008184,8

等等。我已经尝试过 split 函数并且正在努力掌握正则表达式。

Answer 1

不需要正则表达式，你可以使用 split 和 slice 的组合：

s = "0015CB,0,0,01,006D,0016CF1,4,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00F4E7D,1,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0008184,8,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA704,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0014EC8,2,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FAEEA,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FADE9,5,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA5A5,3,000D"

my_list = [e[-9:] for e in s.split(",000D")]
print(my_list)

输出：

['0016CF1,4', '00F4E7D,1', '0008184,8', '00FA704,9', '0014EC8,2', '00FAEEA,9', '00FADE9,5', '00FA5A5,3', '']