SQL 数据库不“保存”通过代码添加的信息（C#）

Question

我正在使用 Dapper 将我的代码连接到我的 LocalDB。我有很多其他函数可以完美地访问信息，可以读取它并将其带入我的程序，但由于某种原因，我将信息插入数据库的函数没有做任何事情。我已经确认没有抛出异常，并且在单击按钮时到达代码（如消息框所示），但没有任何数据保存到数据库中。我还检查了我的查询，当我直接查询数据库时它工作正常，只是当我出于某种原因让代码执行它时（因此是我的问题）。出了什么问题？

using System;
using System.Collections.Generic;
using System.Data;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using Dapper;
using System.Configuration;
using System.Drawing;
using System.Windows.Forms;
using System.Data.SqlClient;

namespace ProjectManager
{
class Database
{
    // Connection Variables
    private IDbConnection connection = new System.Data.SqlClient.SqlConnection(System.Configuration.ConfigurationManager.ConnectionStrings["Database"].ConnectionString);

    // Get Number of Projects
    public int GetNumOfProjects()
    {
        return connection.Query<int>("select count(*) from Projects").FirstOrDefault();
    }
    // Load Projects
    public ProjectPane LoadProjects(int i, Point start)
    {
        // Variables
        string title;
        string subject;
        int progress;

        // Load ProjectPane with Information
        title = connection.Query<string>("select title from (select Row_Number() Over (Order by progress desc) as RowNum, *From Projects) t2 Where RowNum = " + i.ToString()).FirstOrDefault();
        subject = connection.Query<string>("select subject from (select Row_Number() Over (Order by progress desc) as RowNum, *From Projects) t2 Where RowNum = " + i.ToString()).FirstOrDefault();
        progress = connection.Query<int>("select progress from (select Row_Number() Over (Order by progress desc) as RowNum, *From Projects) t2 Where RowNum = " + i.ToString()).FirstOrDefault();

        ProjectPane p = new ProjectPane(title, subject, progress);
        p.Location = start;
        p.LoadData();
        return p;
    }
    // Create Project Entry
    public void CreateProject(string title, string subject, int progress)
    {
        try
        {
            connection.Query($"insert into Projects (title, subject, progress) values ('Hello', 'There', 50)");
            MessageBox.Show("Project Created");
        }
        catch (SqlException ex) 
        {
            MessageBox.Show(ex.ToString());
        }
        
    }
    // Edit Project

    // Complete Projects

    // Delete Project
}

}

Answer 1

使用 Execute 而不是 Query

来源

string sql = "INSERT INTO Customers (CustomerName) Values (@CustomerName);";

using (var connection = new SqlConnection(FiddleHelper.GetConnectionStringSqlServerW3Schools()))
{
    var affectedRows = connection.Execute(sql, new {CustomerName = "Mark"});

    Console.WriteLine(affectedRows);

    var customer = connection.Query<Customer>("Select * FROM CUSTOMERS WHERE CustomerName = 'Mark'").ToList();

    FiddleHelper.WriteTable(customer);
}