绘图条形图 - 根据正/负值更改颜色 - python

Question

我有以下代码绘制条形图（1 个系列），但如果“净”值为正，我需要将条着色为蓝色，如果为负，则将条着色为红色：

import pandas as pd
import plotly.graph_objects as go

df = pd.DataFrame({
     'Net':[15,20,-10,-15], 
     'Date':['07/14/2020','07/15/2020','07/16/2020','07/17/2020']
})

df['Date'] = pd.to_datetime(df['Date'])
fig = go.Figure(data=[go.Bar(name='Net', x=df['Date'], y=df['Net'])])
fig.update_layout(barmode='stack')
fig.show()

Answer 1

您可以在此处查看文档。完整代码如下

import pandas as pd
import plotly.graph_objects as go
import numpy as np

# Data

df = pd.DataFrame({
     'Net':[15,20,-10,-15], 
     'Date':['07/14/2020','07/15/2020','07/16/2020','07/17/2020']
})

df['Date'] = pd.to_datetime(df['Date'])

## here I'm adding a column with colors
df["Color"] = np.where(df["Net"]<0, 'red', 'green')

# Plot
fig = go.Figure()
fig.add_trace(
    go.Bar(name='Net',
           x=df['Date'],
           y=df['Net'],
           marker_color=df['Color']))
fig.update_layout(barmode='stack')
fig.show()