使用NSURL请求时网址错误

Question

我试图在iPhone 4.0 SDK中请求这种URL(访问令牌略有修改,因为你真的不需要看到它):

https://graph.facebook.com/me?sdk=ios&sdk_version=2&access_token=123902817987|8cb9e8408d2685cef853cd80.9-747882379|UGu5NvcAHiXuGEGzkq&format=json&limit=40&until=1286619821

但是我得到了这样的信息:

Failed with error: Error Domain=NSURLErrorDomain Code=-1000 "bad URL" UserInfo=0x9e657a0 {NSUnderlyingError=0x9e656a0 "bad URL", NSLocalizedDescription=bad URL}

当我在Safari或Chrome中复制并粘贴时,它可以正常工作.我试着按照这里的建议进行更换|,但不起作用.%|

从终端询问它看起来像这样:

curl https://graph.facebook.com/me/statuses?sdk=ios&sdk_version=2&access_token=9999955817987|8ab9e8408d2685cef.3-747882379|UGuxWDuM&format=json&limit=40&until=1286619821
[1] 16190
[2] 16191
[3] 16194
[4] 16195
[5] 16196
[2]   Done                    sdk_version=2
[4]-  Done                    format=json
$ -bash: UGu5NvcAHiXuGEGzkq3KP8xWDuM: command not found
-bash: 8ab9e8408d2685cef853cd80.3-747882379: command not found
{"error":{"type":"OAuthException","message":"An active access token must be used to query information about the current user."}}
[1]   Done                    curl https://graph.facebook.com/me/statuses?sdk=ios
[3]-  Exit 127                access_token=9999955817987 | 8ab9e8408d2685cef.3-747882379 | UGuxWDuM
[5]+  Done                    limit=40

有任何想法吗？

Answer 1

 NSString *strURL = [loc_address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

            // requesting weather for this location ... 
            NSMutableURLRequest *req = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:[NSString stringWithFormat: @"http://www.google.com/ig/api?weather=%@", strURL]] cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:5.0];
            [req setHTTPMethod:@"POST"];
            [req addValue:@"text/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];

Answer 2

您需要用URL替换URL中的管道字符%7C.这是URL编码值.

此外,URL需要用引号括起来,以便与curl一起使用.