Aad*_*Ura 3 python dictionary numpy list python-3.x
我有一个 numpy 数组的字典:
{'data1': array([[0.16461831, 0.82400555],
[0.02958593, 0.483629 ],
[0.51268564, 0.07030046],
[0.17027816, 0.35304705]]),
'data2': array([[0.8292598 , 0.78136548],
[0.30389913, 0.69250432],
[0.66608852, 0.42237639],
[0.72678807, 0.40486951]]),
'data3': array([[0.45614633, 0.96677904],
[0.87066105, 0.75826116],
[0.39431988, 0.73041888],
[0.65685809, 0.65498308]])}
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预期输出:
[([0.16461831, 0.82400555], [0.8292598 , 0.78136548], [0.45614633, 0.96677904]),
([0.02958593, 0.483629 ], [0.66608852, 0.42237639], [0.87066105, 0.75826116]),
([0.51268564, 0.07030046], [0.66608852, 0.42237639], [0.39431988, 0.73041888]),
([0.17027816, 0.35304705], [0.72678807, 0.40486951], [0.65685809, 0.65498308])]
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但是当我尝试使用 zip 时:
list(zip(data.values()))
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得到这个输出:
[(array([[0.16461831, 0.82400555],
[0.02958593, 0.483629 ],
[0.51268564, 0.07030046],
[0.17027816, 0.35304705]]),),
(array([[0.8292598 , 0.78136548],
[0.30389913, 0.69250432],
[0.66608852, 0.42237639],
[0.72678807, 0.40486951]]),),
(array([[0.45614633, 0.96677904],
[0.87066105, 0.75826116],
[0.39431988, 0.73041888],
[0.65685809, 0.65498308]]),)]
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如何压缩numpy数组列表?
用
list(zip(*data.values())
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输出:
[(array([0.16461831, 0.82400555]),
array([0.8292598 , 0.78136548]),
array([0.45614633, 0.96677904])),
(array([0.02958593, 0.483629 ]),
array([0.30389913, 0.69250432]),
array([0.87066105, 0.75826116])),
(array([0.51268564, 0.07030046]),
array([0.66608852, 0.42237639]),
array([0.39431988, 0.73041888])),
(array([0.17027816, 0.35304705]),
array([0.72678807, 0.40486951]),
array([0.65685809, 0.65498308]))]
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如果 3D 数组适合您,您可以stack在第二个轴 ( axis=1) 上:
np.stack(data.values(), axis=1)
#[[[0.16461831 0.82400555]
# [0.8292598 0.78136548]
# [0.45614633 0.96677904]]
# [[0.02958593 0.483629 ]
# [0.30389913 0.69250432]
# [0.87066105 0.75826116]]
# [[0.51268564 0.07030046]
# [0.66608852 0.42237639]
# [0.39431988 0.73041888]]
# [[0.17027816 0.35304705]
# [0.72678807 0.40486951]
# [0.65685809 0.65498308]]]
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