Intellij 中无法识别协议缓冲区导入

L. *_*anc 9 java intellij-idea protocol-buffers gradle grpc

我试图将一个协议缓冲区消息导入另一个,但无法识别导入。只要我不尝试将一个 protobuf 导入另一个,就会生成 protobuf 代码(在 Java 中),代码会按预期编译和运行。

我正在使用:

  • Intellij Idea 2020 v1.3 无限版
  • Protobuf 编辑器插件:jvolkman/intellij-protobuf-editor(2020 年 4 月)
  • 摇篮

我的 gradle 构建文件如下所示:

plugins {
    id 'java'
    id 'com.google.protobuf' version "0.8.8"
}

group 'tech.tablesaw'
version '1.0-SNAPSHOT'

sourceCompatibility = 9.0

def grpcVersion = '1.30.1' // CURRENT_GRPC_VERSION
def protobufVersion = '3.12.0'
def protocVersion = protobufVersion

repositories {
    mavenCentral()
}

test {
    useJUnitPlatform()
}

dependencies {
    implementation "io.grpc:grpc-protobuf:${grpcVersion}"
    implementation "io.grpc:grpc-stub:${grpcVersion}"
    compileOnly "org.apache.tomcat:annotations-api:6.0.53"

    // advanced - need this for JsonFormat
    implementation "com.google.protobuf:protobuf-java-util:${protobufVersion}"

    runtimeOnly "io.grpc:grpc-netty-shaded:${grpcVersion}"
    testImplementation "io.grpc:grpc-testing:${grpcVersion}"

    compile group: 'tech.tablesaw', name: 'tablesaw-core', version: '0.38.1'
    testCompile group: 'org.junit.jupiter', name: 'junit-jupiter-engine', version: '5.6.2'
    testImplementation "org.mockito:mockito-core:2.28.2"
}

protobuf {
    protoc { artifact = "com.google.protobuf:protoc:${protocVersion}" }
    plugins {
        grpc { artifact = "io.grpc:protoc-gen-grpc-java:${grpcVersion}" }
    }
    generateProtoTasks {
        all()*.plugins { grpc {} }
    }
}

// Inform IDEs like IntelliJ IDEA, Eclipse or NetBeans about the generated code.
sourceSets {
    main {
        java {
            srcDirs 'build/generated/source/proto/main/grpc'
            srcDirs 'build/generated/source/proto/main/java'
        }
    }
}

task TablesawServer(type: CreateStartScripts) {
    mainClassName = 'tech.tablesaw.service.TableServiceServer'
    applicationName = 'tablesaw-table-server'
    outputDir = new File(project.buildDir, 'tmp')
}

task TablesawClient(type: CreateStartScripts) {
    mainClassName = 'tech.tablesaw.service.TableServiceClient'
    applicationName = 'tablesaw-table-client'
    outputDir = new File(project.buildDir, 'tmp')
}
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我的 gradle 信息如下所示:

------------------------------------------------------------
Gradle 5.1.1
------------------------------------------------------------

Build time:   2019-01-10 23:05:02 UTC
Revision:     3c9abb645fb83932c44e8610642393ad62116807

Kotlin DSL:   1.1.1
Kotlin:       1.3.11
Groovy:       2.5.4
Ant:          Apache Ant(TM) version 1.9.13 compiled on July 10 2018
JVM:          9.0.4 (Oracle Corporation 9.0.4+11)
OS:           Mac OS X 10.13.5 x86_64
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这是一个示例 protobuf。column_type.proto 的导入失败。

syntax = "proto3";

package tech.tablesaw.service.common;

import "tech/tablesaw/service/common/column_type.proto";

option java_multiple_files = true;
option java_package = "tech.tablesaw.service.common";
option java_outer_classname = "ColumnMetaProto";
option objc_class_prefix = "TSW";

// Proto file describing column metadata message.

// A column metadata object
message ColumnMetadata {

  string name = 1;
  int32 size = 2;
  ColumnTypeEnum.ColumnType column_type = 3;
}

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这是我要导入的文件:

syntax = "proto3";

package tech.tablesaw.service.common;

option java_multiple_files = true;
option java_package = "tech.tablesaw.service.common";
option java_outer_classname = "ColumnTypeEnum";
option objc_class_prefix = "TSW";

enum ColumnType {
  SHORT = 0;
  INTEGER = 1;
  LONG = 2;
  FLOAT = 3;
  BOOLEAN = 4;
  STRING = 5;
  DOUBLE = 6;
  LOCAL_DATE = 7;
  LOCAL_TIME = 8;
  LOCAL_DATE_TIME = 9;
  INSTANT = 10;
  TEXT = 11;
  SKIP = 12;
}

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最后,这是 protobufs 在文件系统中的位置。

src > main > java
           > proto > tech > tablesaw > service > common > column_metadata.proto
                                                        > column_type.proto
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小智 14

查看描述如何添加其他路径的自述文件。

默认情况下,intellij-protobuf-editor使用项目配置的源根作为 protobuf 导入路径。如果这不正确,您可以在Settings > Languages & Frameworks > Protocol Buffers. 取消选中“自动配置”并添加您需要的任何路径。在您的情况下,您将添加.../src/main/java/proto(其中...意味着您项目的基本路径是什么)。