从Android插入联系人到SIM卡

use*_*953 6 android android-emulator android-layout

我尝试将Android联系人应用程序中存在的联系人复制到SIM卡时遇到问题.以下是代码:

ContentValues cv = new ContentValues();
cv.put("tag", cName);
cv.put("number", cNumber);

Uri uri = context.getContentResolver().insert(SIM_CONTENT_URI, cv);
Log.d(TAG_LOG, "URI is : " + uri);
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我在cName和cNumber变量中有值.但是当我打印日志以查看uri变量的值时:它为null.

任何人都可以告诉我,如果我在上面的代码中出错插入SIM卡?

Kir*_*ran 0

试试这个代码..

String name = "First Family";
String phone = "0123456789";
ContentValues values = new ContentValues();
values.put(Data.DISPLAY_NAME, name);
Uri rawContactUri = c.getContentResolver().insert(RawContacts.CONTENT_URI, values);
long rawContactId = ContentUris.parseId(rawContactUri);
long contactId = Util.getContactId(c, rawContactId);
System.out.println("rawContactId = " + rawContactId);
System.out.println("contactId = " + contactId);

values.clear();
values.put(Phone.NUMBER, phone);
values.put(Phone.TYPE, Phone.TYPE_OTHER);
values.put(Phone.MIMETYPE, Phone.CONTENT_ITEM_TYPE);
values.put(Data.RAW_CONTACT_ID, rawContactId);
c.getContentResolver().insert(Data.CONTENT_URI, values);

values.clear();
values.put(Data.MIMETYPE, Data.CONTENT_TYPE);
values.put(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME, name);
values.put(Data.RAW_CONTACT_ID, rawContactId);
c.getContentResolver().insert(Data.CONTENT_URI, values);

values.clear();
values.put(Data.MIMETYPE, StructuredName.CONTENT_ITEM_TYPE);
values.put(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME, name);
values.put(Data.RAW_CONTACT_ID, rawContactId);
c.getContentResolver().insert(Data.CONTENT_URI, values);



public static long getContactId(Context context, long rawContactId) {
Cursor cur = null;
try {
    cur = context.getContentResolver().query(ContactsContract.RawContacts.CONTENT_URI, new String[] { ContactsContract.RawContacts.CONTACT_ID }, ContactsContract.RawContacts._ID + "=" + rawContactId, null, null);
    if (cur.moveToFirst()) {
        return cur.getLong(cur.getColumnIndex(ContactsContract.RawContacts.CONTACT_ID));
    }
} catch (Exception e) {
    e.printStackTrace();
} finally {
    if (cur != null) {
        cur.close();
    }
}
return -1l;
}
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