XPath基于复杂过滤器计算子节点

Question

我有一个XML格式如下:

<ComRequest>
  <root lineId="1" creator="jumnix">
    <component lineId="101">
        <compLine lineId="1001">1</compLine>
        <compLine lineId="1002">2</compLine>
        <compLine lineId="1003">3</compLine>
        <compLine lineId="1004">4</compLine>
        <compLine lineId="1005">5</compLine>
        <compLine lineId="1006">6</compLine>
        <compLine lineId="1007">7</compLine>
        <compLine lineId="1008">8</compLine>
        <compLine lineId="1009">9</compLine>
        <compLine lineId="1010">10</compLine>
        <compLine lineId="1011">11</compLine>
    </component>
    <component lineId="102">
        <compLine lineId="1012">12</compLine>
        <compLine lineId="1013">13</compLine>
        <compLine lineId="1014">14</compLine>
        <compLine lineId="1015">15</compLine>
        <compLine lineId="1016">16</compLine>
        <compLine lineId="1017">17</compLine>
        <compLine lineId="1018">18</compLine>
        <compLine lineId="1019">19</compLine>
        <compLine lineId="1020">20</compLine>
        <compLine lineId="1021">21</compLine>
        <compLine lineId="1022">22</compLine>
    </component>
  </root>
</ComRequest>

我需要获得具有10个'compLine'元素的'组件'节点的计数.直到现在我有以下XPath查询 -

count(//*[local-name()='ComRequest']/*[local-name()='root']/*[local-name()='component']/*[local-name()='compLine' and count(self) gt 10])

但这不起作用(给出'0'结果).任何有助于解决此问题的帮助表示赞赏.

Answer 1

怎么样count(//ComRequest/root/component[count(compLine)>10])？