bra*_*age 5 java performance multithreading
我正在尝试计算Pi,但我真正想要实现的是使用多个线程时的效率.算法很简单:我在单位平方中随机生成点,然后计算其中有多少点位于正方形内的圆中.(更多这里:http://math.fullerton.edu/mathews/n2003/montecarlopimod.html)我的想法是水平分割方块并为其每个部分运行不同的线程.但不是加速,我得到的只是延迟.有什么想法吗?这是代码:
public class TaskManager {
public static void main(String[] args) {
int threadsCount = 3;
int size = 10000000;
boolean isQuiet = false;
PiCalculator pi = new PiCalculator(size);
Thread tr[] = new Thread[threadsCount];
long time = -System.currentTimeMillis();
int i;
double s = 1.0/threadsCount;
int p = size/threadsCount;
for(i = 0; i < threadsCount; i++) {
PiRunnable r = new PiRunnable(pi, s*i, s*(1.0+i), p, isQuiet);
tr[i] = new Thread(r);
}
for(i = 0; i < threadsCount; i++) {
tr[i].start();
}
for(i = 0; i < threadsCount; i++) {
try {
tr[i].join();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
double myPi = 4.0*pi.getPointsInCircle()/pi.getPointsInSquare();
System.out.println(myPi + " time = " + (System.currentTimeMillis()+time));
}
}
public class PiRunnable implements Runnable {
PiCalculator pi;
private double minX;
private double maxX;
private int pointsToSpread;
public PiRunnable(PiCalculator pi, double minX, double maxX, int pointsToSpread, boolean isQuiet) {
super();
this.pi = pi;
this.minX = minX;
this.maxX = maxX;
this.pointsToSpread = pointsToSpread;
}
@Override
public void run() {
int n = countPointsInAreaInCircle(minX, maxX, pointsToSpread);
pi.addToPointsInCircle(n);
}
public int countPointsInAreaInCircle (double minX, double maxX, int pointsCount) {
double x;
double y;
int inCircle = 0;
for (int i = 0; i < pointsCount; i++) {
x = Math.random() * (maxX - minX) + minX;
y = Math.random();
if (x*x + y*y <= 1) {
inCircle++;
}
}
return inCircle;
}
}
public class PiCalculator {
private int pointsInSquare;
private int pointsInCircle;
public PiCalculator(int pointsInSquare) {
super();
this.pointsInSquare = pointsInSquare;
}
public synchronized void addToPointsInCircle (int pointsCount) {
this.pointsInCircle += pointsCount;
}
public synchronized int getPointsInCircle () {
return this.pointsInCircle;
}
public synchronized void setPointsInSquare (int pointsInSquare) {
this.pointsInSquare = pointsInSquare;
}
public synchronized int getPointsInSquare () {
return this.pointsInSquare;
}
}
Run Code Online (Sandbox Code Playgroud)
一些结果: - 3个线程:"3.1424696时间= 2803" - 1个线程:"3.1416192时间= 2337"
jos*_*efx 10
你的线程可能正在战斗/等待Math.random()哪个是同步的,你应该为每个线程创建一个java.util.Random实例.此外,在这种情况下,如果您有多个核心/ CPU,则只会发生多线程加速.
从Math.random()的javadoc :
此方法已正确同步,以允许多个线程正确使用.但是,如果许多线程需要以很高的速率生成伪随机数,则可以减少每个线程拥有自己的伪随机数生成器的争用.
| 归档时间: |
|
| 查看次数: |
5096 次 |
| 最近记录: |