sha*_*er1 6 jquery json getjson
我试图使用grep过滤json对象数组,以便搜索数组,如果任何键#2-6的值为yes,则返回键1和7的值.
数组在下面 - 换句话说,如果'location'键的任何值为yes,则名称和描述将作为列表项返回.
很感谢任何形式的帮助.
[
{
"name": "name",
"location1": "no",
"location2": "no",
"location3": "yes",
"location4": "no",
"location5": "no",
"description": "description of services"
},
{
"name": "name",
"location1": "yes",
"location2": "no",
"location3": "yes",
"location4": "no",
"location5": "no",
"description": "description of services"
}
]
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mVC*_*Chr 13
你需要同时使用grep和map.如果a是上述的阵列(但是name1,name2等),在此之后执行以下操作:
var b = $.grep(a, function(el, i) {
return el.location1.toLowerCase() === "yes"
|| el.location2.toLowerCase() === "yes"
|| el.location3.toLowerCase() === "yes"
|| el.location4.toLowerCase() === "yes"
|| el.location5.toLowerCase() === "yes";
});
var c = $.map(b, function(el, i) {
return {
name: el.name,
description: el.description
};
});
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c 将包含 [{"name":"name1","description":"description of services1"},{"name":"name2","description":"description of services2"}]
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