PHP解码json

Jas*_*ell 1 php api json decode

谁能在这里帮助我解决json的解码?我试图解码一个json api url

这就是我现在所拥有的:

  $string = '
    {
        "username": "someusername",
        "unconfirmed_reward": "0.08681793",
        "send_threshold": "0.01000000",
        "confirmed_reward": "0.02511418",
         "workers":
        {
        "bitcoinjol.jason-laptop": {"last_share": 1307389634, "score": "0", "hashrate": 0, "shares": 0, "alive": false},
        "bitcoinjol.david-laptop": {"last_share": 1307443495, "score": "1.7742", "hashrate": 24, "shares": 1, "alive": true},
        "bitcoinjol.pierre-pc": {"last_share": 1307441804, "score": "0", "hashrate": 0, "shares": 0, "alive": true},
        "bitcoinjol.testJol": {"last_share": 0, "score": "0", "hashrate": 0, "shares": 0, "alive": false}
        },
        "wallet": "asdasdjsadajdasjdsajasjdajdajs",
        "estimated_reward": "0.00131061"
    }';

    $json_o = json_decode($string);
    echo $json_o->username;
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这打印出"someusername",但是当我尝试时,我无法打印出工人:

echo $json_o->workers->someusername.jason-laptop;
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我认为是"." 或者我使用的" - "无效?

我希望能够打印出每个工人,然后使用数组或这些对象打印出waller,用户名和奖励等.我也尝试将$ String拆分为","然后爆炸,但不能让它工作得很好.

使用php 5.3和IIS 7.5运行Server 2008 R2

Gum*_*mbo 6

花括号语法应该有效:

$json_o->workers->{"someusername.jason-laptop"}
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Fél*_*lli 5

您可以使用Gumbo建议的花括号语法:

$json_o->workers->{"someusername.jason-laptop"}
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但是,最好的方法(imo,为了保持一致性)是将结果对象用作关联数组:

$object = json_decode($string, true);

$object['workers']['bitcoinjol.jason-laptop']['last_share']; // 1307389634
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