Ian*_*.T 3 if-statement r dplyr tidyverse
我认为如果我显示问题是什么会更容易,所以我有这个数字数据
MoSold YrSold SalePrice OverallQual OverallCond
1 2 3 208500 7 5
2 5 2 181500 6 8
3 9 3 223500 7 5
4 2 1 140000 7 5
5 12 3 250000 8 5
6 10 4 143000 5 5
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感谢 mutate_at 和嵌套的 ifelse,如果条件为真(列平均值高于 0.8),我想更改每一行,但是当我尝试使用此代码执行此操作时
data %>%
mutate_at(vars(MoSold, YrSold, SalePrice, OverallQual, OverallCond),
~(ifelse((mean(., na.rm = T)) > 4, log(.), .))) %>% head()
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我得到以下数据,所有列都具有相同的值
MoSold YrSold SalePrice OverallQual OverallCond
1 0.6931472 3 12.24769 1.94591 1.609438
2 0.6931472 3 12.24769 1.94591 1.609438
3 0.6931472 3 12.24769 1.94591 1.609438
4 0.6931472 3 12.24769 1.94591 1.609438
5 0.6931472 3 12.24769 1.94591 1.609438
6 0.6931472 3 12.24769 1.94591 1.609438
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如果条件为真,我希望获得每行相应值的日志,如果条件为假,则获得原始值
我知道一种解决方案是使用 for 循环,但我真的很喜欢使用 dplyr/tidyverse 的解决方案
提前致谢
我。
mean该问题与用作testfor相关ifelse,它是单个值,而“yes”、“no”参数的长度不同,即结果为单个 TRUE/FALSE 的逻辑表达式,并且这会被复制为完整的值。回收“yes”、“no”第一个元素的长度
在这里,我们可以if/else使用ifelse
library(dplyr)
data %>%
mutate_all(~ if(mean(., na.rm = TRUE) > 4) log(.) else .)
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在dplyr1.0.0 中,一个选项是mutate/across
data %>%
mutate(across(everything(),
~ if(mean(., na.rm = TRUE) > 4) log(.) else .))
# MoSold YrSold SalePrice OverallQual OverallCond
#1 0.6931472 3 12.24769 1.945910 1.609438
#2 1.6094379 2 12.10901 1.791759 2.079442
#3 2.1972246 3 12.31717 1.945910 1.609438
#4 0.6931472 1 11.84940 1.945910 1.609438
#5 2.4849066 3 12.42922 2.079442 1.609438
#6 2.3025851 4 11.87060 1.609438 1.609438
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如果我们想使用ifelse,请复制单个逻辑值以使所有 'test'、'yes'、'no' 具有相同的长度
data %>%
mutate_at(vars(MoSold, YrSold, SalePrice, OverallQual, OverallCond),
~(ifelse(rep((mean(., na.rm = T)) > 4, n()), log(.), .)))
# MoSold YrSold SalePrice OverallQual OverallCond
#1 0.6931472 3 12.24769 1.945910 1.609438
#2 1.6094379 2 12.10901 1.791759 2.079442
#3 2.1972246 3 12.31717 1.945910 1.609438
#4 0.6931472 1 11.84940 1.945910 1.609438
#5 2.4849066 3 12.42922 2.079442 1.609438
#6 2.3025851 4 11.87060 1.609438 1.609438
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data <- structure(list(MoSold = c(2L, 5L, 9L, 2L, 12L, 10L), YrSold = c(3L,
2L, 3L, 1L, 3L, 4L), SalePrice = c(208500L, 181500L, 223500L,
140000L, 250000L, 143000L), OverallQual = c(7L, 6L, 7L, 7L, 8L,
5L), OverallCond = c(5L, 8L, 5L, 5L, 5L, 5L)), class = "data.frame",
row.names = c("1",
"2", "3", "4", "5", "6"))
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