Tah*_*qui 4 javascript node.js
代码按预期工作正常,但name响应中缺少参数。
var objArr= [{'location_id':1,'quantity':20,'name':'AB'},{'location_id':1,'quantity':20,'name':'AB'},{'location_id':3,'quantity':20,'name':'cd'}]
// first, convert data into a Map with reduce
let counts = objArr.reduce((prev, curr) => {
  let count = prev.get(curr.location_id) || 0;
  prev.set(curr.location_id, (curr.quantity + count),curr.name);
  return prev;
}, new Map());
// then, map your counts object back to an array
let reducedObjArr = [...counts].map(([location_id, quantity,name]) => {
  return {location_id, quantity,name}
})
console.log (reducedObjArr);预期回应:
[
{"location_id":1,"quantity":40, "name":'AB'},
{"location_id":3,"quantity":20, "name":'cd'}
]
最简单的方法:
const objArr = 
    [ { location_id: 1, quantity: 20, name: 'AB' } 
    , { location_id: 1, quantity: 20, name: 'AB' } 
    , { location_id: 3, quantity: 20, name: 'cd' } 
    ] 
     
const sum = objArr.reduce((a,c)=>{
  let x = a.find(e=>e.location_id===c.location_id)
  if(!x) a.push(Object.assign({},c))
  else  x.quantity += c.quantity
  return a
},[])
console.log(sum).as-console-wrapper { max-height: 100% !important; top: 0; }| 归档时间: | 
 | 
| 查看次数: | 619 次 | 
| 最近记录: |