问题在ruby中支持双向语法

Question

我有一种情况需要调用这样的东西:

class Office

  attr_accessor :workers, :id

  def initialize
    @workers = []
  end

  def workers worker
    type = worker.type
    resp = Worker.post("/office/#{@id}/workers.json", :worker => {:type => type})
    worker = Worker.new()
    resp.to_hash.each_pair do |k,v|
      worker.send("#{k}=",v) if worker.respond_to?(k)
    end
    self.workers << worker
  end

end

工人阶级

class Worker
  attr_accessor :office_id, :type, :id

  def initialize(options={})
    @office_id = options[:office].nil? ? nil : options[:office].id
    @type = options[:type].nil? ? nil : options[:type].camelize
    if !@office_id.nil?
       resp = self.class.post("/office/#{@office_id}/workers.json", :worker => {:type => @type})
       @id = resp.id
       office = options[:office]
       office.workers = self
    end
  end

  def <<(worker)
    if worker
      type = worker.type
      resp = Worker.post("/office/#{office_id}/workers.json", :worker => {:type => type})
      debugger
      @id = resp.id
      resp.to_hash.each_pair do |k,v|
        self.send("#{k}=",v) if self.respond_to?(k)
      end
      debugger
      return self
    end
  end

我可以做这样的事情

office = Office.new()
new_worker = Worker.new()
office.workers new_worker

但我需要做同样的事情,如上所述.在此之前,我需要更改Office的初始化方法以启动def <<(worker)工作器实例的方法.

class Office
  ...
  def initialize
    @workers = Worker.new
    @workers.office_id = self.id
  end


office = Office.new()
new_worker = Worker.new()
office.workers << new_worker

现在问题是,后面的实现创建了2个工人实例？

Answer 1

我不是 100% 确定为什么您在这里没有收到错误，但由于 Office#workers 最后一行是 self.workers <<worker，因此您正在添加在 Office#workers 中创建的新工作人员（在第 3 行创建）方法），然后返回工人对象，然后使用在方法外部创建的新工人再次调用 #<<