如何使用node.js列出目录IN ORDER的内容？
Bra*_*don 12 javascript directory list node.js inorder
我是一个相当有经验的程序员,我刚刚发现了node.js. 我喜欢JavaScript,因为那是我开始的地方(Web开发)所以能够用它来编写服务器端代码是非常了不起的.
目前,我正在进行一个简单的练习,一个WebSocket/HTTP服务器,当我遇到一个轻微的烦恼时,我开始添加目录列表功能:当我列出某个目录中的目录和文件时,它们不在任何订购.我希望它们首先列出目录,然后按字母顺序列出文件(比如'ls'命令).我有一种感觉,因为它的异步,但我并不完全正面.任何帮助,将不胜感激.
顺便说一句,这是我的代码:
var sys = require("sys");
var ws = require('websocket-server');
var fs = require("fs");
var path = require("path");
var url = require("url");
function log(data){
sys.log("\033[0;32m"+data+"\033[0m");
}
var server = ws.createServer();
server.listen(3400);
log("Listening on 3400 for HTTP and WS");
server.addListener("request", function(request, response){
log("HTTP: Connected: " + request.connection.remoteAddress);
var uri = url.parse(request.url).pathname;
var filename = path.join("/home/brandon", uri);
log("HTTP: " + request.connection.remoteAddress + " Requested: " + filename);
path.exists(filename, function(exists) {
if(!exists) {
response.writeHead(404, {"Content-Type": "text/plain"});
response.write("404 Not Found\n");
log("HTTP: " + filename + " Does Not Exist. 404 returned to " + request.connection.remoteAddress);
response.end();
log("HTTP: Disconnected: " + request.connection.remoteAddress);
return;
}
fs.readFile(filename, "binary", function(err, file) {
if(err) {
if(err.errno === 21){
fs.readdir(filename, function(err1, files){
if(err1){
response.writeHead(500, {"Content-Type": "text/plain"});
response.write("Error when reading directory: " + err1 + "\n");
log("HTTP: " + filename + " Could Not Be Read. 500 returned to " + request.connection.remoteAddress);
response.end();
log("HTTP: Disconnected: " + request.connection.remoteAddress);
return;
} else {
response.writeHead(200);
response.write("<HTML><HEAD><title>Directory Listing for " + uri + "</title></HEAD><BODY><h1>Directory Listing for " + uri + "</h1>");
response.write("<ul>");
function printBr(element, index, array) {
response.write("<li>" + element + "</li>");
}
/*for( i in files ){
response.write("<li>" + files[i] + "</li>");
}*/
files.forEach(printBr);
response.write("</ul>");
response.write("</BODY></HTML>");
log("HTTP: Directory listing for " + filename + " sent to " + request.connection.remoteAddress);
response.end();
log("HTTP: Disconnected: " + request.connection.remoteAddress);
return;
}
});
return;
}
response.writeHead(500, {"Content-Type": "text/plain"});
response.write("Error when reading file: " + err + "\n");
log("HTTP: " + filename + " Could Not Be Read. 500 returned to " + request.connection.remoteAddress);
response.end();
log("HTTP: Disconnected: " + request.connection.remoteAddress);
return;
}
response.writeHead(200);
response.write(file, "binary");
log("HTTP: " + filename + " Read and Sent to " + request.connection.remoteAddress);
response.end();
log("HTTP: Disconnected: " + request.connection.remoteAddress);
});
});
});
server.addListener("connection", function(conn){
log(conn.id + ": new connection");
server.broadcast("New Connection: "+conn.id);
conn.addListener("readyStateChange", function(readyState){
log("stateChanged: "+readyState);
});
conn.addListener("close", function(){
var c = this;
log(c.id + ": Connection Closed");
server.broadcast("Connection Closed: "+c.id);
});
conn.addListener("message", function(message){
log(conn.id + ": "+JSON.stringify(message));
server.broadcast(conn.id + ": "+message);
});
});
这是浏览器中的输出:
**解决了:**
感谢@Samir,我发现了如何做我想做的事情.我遍历目录内容的数组,检查项目是否是目录或文件,将它们分成两个数组(dirs的'dirs_in'和文件的'files_in'),按字母顺序排列两个数组,最后写出来.
代码(第42-70行):
response.writeHead(200);
response.write("<HTML><HEAD><title>Directory Listing for " + uri + "</title></HEAD><BODY><h1>Directory Listing for " + uri + "</h1>");
response.write("<ul>");
function printBr(element, index, array) {
response.write("<li>" + element);
if( fs.statSync( path.join(filename + element) ).isDirectory() ){
response.write(" is a <b>dir</b>");
} else {
response.write(" is a <b>file</b>");
}
response.write("</li>");
}
var dirs_in = [];
var files_in = [];
function sep(element, index, array) {
if( fs.statSync( path.join(filename + element) ).isDirectory() ){
dirs_in.push(element);
} else {
files_in.push(element);
}
}
files.forEach(sep);
dirs_in.sort().forEach(printBr);
files_in.sort().forEach(printBr);
response.write("</ul>");
response.write("</BODY></HTML>");
log("HTTP: Directory listing for " + filename + " sent to " + request.connection.remoteAddress);
response.end();
log("HTTP: Disconnected: " + request.connection.remoteAddress);
浏览器输出:
PS我将删除'是一个dir'和'是一个文件'.它们只是用于测试.
Sam*_*war 13
如果您希望按名称排序,则可以sort()先调用阵列.
files.sort().forEach(printBr);
例如,如果您想首先对目录进行排序,那么您需要获取更多信息.一个简单的实现是查询排序比较函数中每个文件的统计信息:
files.sort(function(a, b) {
var aIsDir = fs.statSync(dir + "/" + a).isDirectory(),
bIsDir = fs.statSync(dir + "/" + b).isDirectory();
if (aIsDir && !bIsDir) {
return -1;
}
if (!aIsDir && bIsDir) {
return 1;
}
return a.localCompare(b);
}).forEach(printBr);
该localCompare方法是sort默认情况下该方法用作比较函数的方法,因此如果它们都是"相等"条件,我们就委托给它.您可以根据需要进行扩展.我还建议您isDirectory至少将结果存储在地图或其他内容中.此外,statSync有助于演示目的,但不适用于生产代码.请stat改用.这确实会导致稍微复杂的代码,但异步行为的好处是值得的.
- @Raynos:这部分是我所说的"天真".如何使用异步函数取决于您的样式及其周围的代码.在某些时候你将不得不敲打某种闩锁,这实际上超出了这个问题的范围.我将添加有关如何使用`stat`来回答问题的信息. (5认同)
- -1 用于使用“同步”功能。他们创造了可怕的瓶颈。 (2认同)
| 归档时间： |
|
| 查看次数： |
20751 次 |
| 最近记录： |