如何在flutter中的primarySwatch中分配十六进制颜色代码?

Ram*_*uam 9 flutter

我想在 PrimarySwatch 属性中插入十六进制颜色代码,这是我尝试做的:

           return MaterialApp(
             title: 'Login Demo',
             theme: ThemeData(
              // brightness: Brightness.dark,
               primarySwatch: Color(0xFF3399FF),
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Gil*_*ton 17

教程展示了一个可以从Color.

MaterialColor buildMaterialColor(Color color) {
  List strengths = <double>[.05];
  Map<int, Color> swatch = {};
  final int r = color.red, g = color.green, b = color.blue;

  for (int i = 1; i < 10; i++) {
    strengths.add(0.1 * i);
  }
  strengths.forEach((strength) {
    final double ds = 0.5 - strength;
    swatch[(strength * 1000).round()] = Color.fromRGBO(
      r + ((ds < 0 ? r : (255 - r)) * ds).round(),
      g + ((ds < 0 ? g : (255 - g)) * ds).round(),
      b + ((ds < 0 ? b : (255 - b)) * ds).round(),
      1,
    );
  });
  return MaterialColor(color.value, swatch);
}

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然后在主题中你可以这样做:

      primarySwatch: buildMaterialColor(Color(0xFF3399FF)),
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  • 如果有人收到 Error: The argument type 'Map&lt;dynamic,dynamic&gt;' can't be分配给参数类型 'Map&lt;int, Color&gt;',请尝试更改行:Map swatch = &lt;int, Color&gt;{ }; 至:Map&lt;int, Color&gt; 样本 = {}; (2认同)