工会中的 Laravel 关系冲突

Question

我有以下模型：1-用户模型

 /**
 * Define user and functional area relationship
 */
public function functionalAreas()
{
    return $this->belongsToMany('App\FunctionalArea', 'user_functional_areas', 'user_id', 'functional_area_id')->withPivot('id', 'is_primary')->withTimestamps();
}

和商业模式：

 /**
 * Define business and user functional area relationship
 */
public function functionalAreas()
{
    return $this->belongsToMany('App\FunctionalArea', 'business_functional_areas', 'business_id', 'functional_area_id')->withTimestamps();
}

现在我应该将所有企业和用户显示在一个列表中，为此我使用来自 union，以下是我的查询：

public function usersAndOrganizations()
{
    $users = $this->users();

    $organizations = $this->organizations();

    $invitees = $users->union($organizations)->paginate(10);
    
    return response()->json($invitees);
}

private function users()
{
    $users = User::byState($approved = true, 'is_approved')
        ->search()->select([
            'id',
            DB::raw("CONCAT(first_name, ' ', last_name) AS name"),
            'about',
            'address',
            'slug',
            'average_reviews',
            DB::raw("'freelancer' AS type")
        ]);

  $users = $users->with([
        "functionalAreas" => function ($q) {
            $q->select([
                'functional_areas.id',
                DB::raw("functional_areas.name_en AS name"),
            ]);
        }
    ]);
    return $users;
}
 

private function organizations()
{
    $businesses = Business::where('owner_id', '!=', auth()->user()->id)->verified()
        ->active()->search()
        ->select([
            'id',
            'name',
            'about',
            'address',
            'slug',
            'average_reviews',
            DB::raw("'business' AS type")
        ]); 
        $businesses = $businesses
            ->with([
            "functionalAreas" => function ($q) {
                $q->select([
                    'functional_areas.id',
                    DB::raw("functional_areas.name_en AS name"),
                ]);
            }
        ]);
        return $businesses;
} 

但是上面的查询没有返回业务功能区，它的输出查询使用来自用户关系而不是业务，该with部分生成了两次以下查询：

select
  `functional_areas`.`id`,
  functional_areas.name_en AS name,
  `user_functional_areas`.`user_id` as `pivot_user_id`,
  `user_functional_areas`.`functional_area_id` as `pivot_functional_area_id`,
  `user_functional_areas`.`id` as `pivot_id`,
  `user_functional_areas`.`is_primary` as `pivot_is_primary`,
  `user_functional_areas`.`created_at` as `pivot_created_at`,
  `user_functional_areas`.`updated_at` as `pivot_updated_at`
from `functional_areas`
inner join `user_functional_areas`
  on `functional_areas`.`id` = `user_functional_areas`.`functional_area_id`
where `user_functional_areas`.`user_id` in (2, 6, 7)

但实际上 6 和 7 是业务 id 而不是 user only 2 是用户 id，这个查询之一应该使用business_functional_areas而不是user_functional_areas. 发现的另一件事是，结果中所有项目都在App\User模型内，它的喜欢businesses也作为用户对象。

Answer 1

目前唯一的方法是使用 from map。

public function usersAndOrganizations()
{
    $users = $this->users();

    $organizations = $this->organizations();

    $invitees = $users->union($organizations)->paginate(10);
  
    $invitees = $this->getRelatedData($invitees);

    return response()->json($invitees);
}


private function getRelatedData($invitees)
{
    $invitees->map(function($object) use($functionalAreaName) {
        if($object->type == 'business') {
            $relationName = 'businesses';
            $relationKey = 'business_id';
            $attachableType = Business::MORPHABLE_TYPE;
        }
        if($object->type == 'freelancer') {
            $relationName = 'users';
            $relationKey = 'user_id';
            $attachableType = User::MORPHABLE_TYPE;
        }
        $functionalAreas = FunctionalArea::whereHas($relationName, function($q) use ($object, $relationKey){
            $q->where($relationKey, $object->id);
        })->get([$functionalAreaName.' As name', 'id']);

        $object->functional_areas =  $functionalAreas->toArray();

    });

    return $invitees;
}

并with从您的函数中删除，并在获得分页结果后调用它。