Ron*_*eld 2 javascript arrays jsx reactjs
我有一个数组,比如说
[
{
lesson: 1,
title: "Welcome",
slug: "welcome",
active: active,
breakDay: false,
started_time: new Date(),
finished_time: null,
completed: true,
sublesson: [
{
lesson: 1.1,
title: "Evaluation",
slug: 'evaluation',
completed: false,
answers: []
}
],
answers: []
},
{
lesson: 2,
title: "Example",
slug: "example",
active: active,
breakDay: false,
started_time: null,
finished_time: null,
completed: false,
sublesson: [
{
lesson: 2.1,
title: "example2,
slug: 'example2,
answers: []
}
],
answers: []
}
]
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我需要找到一种方法来制定第一个项目以达到特定条件。
我在我的 React 应用程序中尝试过,但很快意识到它实际上是在检查第一个项目而不是整个数组的这些条件是否为真。
{
lessons !== null ?
lessons.map((item, index, arr) => (
index === 0 && item.active === true ?
<>
<p>{item.title}</p>
</>
:
null
))
:
null
}
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所以本质上,我如何过滤第一项,以满足特定条件,例如item.active === true && item.completed === false?
您可能需要filter这里:
var data=[ { lesson: 1, title: "Welcome", slug: "welcome", active: 'active', breakDay: false, started_time: new Date(), finished_time: null, completed: true, sublesson: [ { lesson: 1.1, title: "Evaluation", slug: 'evaluation', completed: false, answers: [] } ], answers: [] }, { lesson: 2, title: "Example", slug: "example", active: 'active', breakDay: false, started_time: null, finished_time: null, completed: false, sublesson: [ { lesson: 2.1, title: "example2", slug: 'example2', answers: [] } ], answers: [] }];
var result = data.filter(({active, completed})=> active && !completed);
console.log(result);Run Code Online (Sandbox Code Playgroud)
或者find获取第一个匹配的对象:
var data=[ { lesson: 1, title: "Welcome", slug: "welcome", active: 'active', breakDay: false, started_time: new Date(), finished_time: null, completed: true, sublesson: [ { lesson: 1.1, title: "Evaluation", slug: 'evaluation', completed: false, answers: [] } ], answers: [] }, { lesson: 2, title: "Example", slug: "example", active: 'active', breakDay: false, started_time: null, finished_time: null, completed: false, sublesson: [ { lesson: 2.1, title: "example2", slug: 'example2', answers: [] } ], answers: [] }];
var result = data.find(({active, completed})=> active && !completed);
console.log(result);Run Code Online (Sandbox Code Playgroud)
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