使用 RASA API 的正确方法是什么（rasa.core.processor - 遇到异常）？

Question

我安装了 rasa-demo 代码示例。为了打开 rasa API，我做了：

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user@User:~/rasa-demo \xe2\x80\xb9master*\xe2\x80\xba$ rasa run\nNo chat connector configured, falling back to the REST input channel. To connect your bot to another channel, read the docs here: https://rasa.com/docs/rasa/user-guide/messaging-and-voice-channels\n2020-06-19 13:20:02 INFO     root  - Starting Rasa server on http://localhost:5005\n2020-06-19 13:20:08 INFO     absl  - Using /var/folders/h5/9rj1zn8x4s59bk_mg_ktzv740000gn/T/tfhub_modules to cache modules.\n2020-06-19 13:20:08 INFO     absl  - Downloading TF-Hub Module \'http://models.poly-ai.com/convert/v1/model.tar.gz\'.\n2020-06-19 13:20:26 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 22.35MB\n2020-06-19 13:20:43 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 42.35MB\n2020-06-19 13:21:02 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 82.35MB\n2020-06-19 13:21:21 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 118.59MB\n2020-06-19 13:21:40 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 148.59MB\n2020-06-19 13:21:41 INFO     absl  - Downloaded http://models.poly-ai.com/convert/v1/model.tar.gz, Total size: 152.02MB\n2020-06-19 13:21:41 INFO     absl  - Downloaded TF-Hub Module \'http://models.poly-ai.com/convert/v1/model.tar.gz\'.\n2020-06-19 13:22:14 INFO     root  - Rasa server is up and running.\n

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如何以 API 形式查询聊天机器人？我希望能够发出请求并通过请求进行对话，而不是使用 shell。到目前为止，当我尝试对 rasa 服务器进行卷曲时：

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在：

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user@User:~ $ curl -XPOST localhost:5005/webhooks/rest/webhook -d \'{"message":"hi"}\'\n

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出去：

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[]%\n

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在 rasa run 服务器上，我得到以下响应：

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2020-06-19 13:23:17 ERROR    rasa.core.actions.action  - Failed to run custom action \'action_greet_user\'. Couldn\'t connect to the server at \'http://localhost:5055/webhook\'. Is the server running? Error: Cannot connect to host localhost:5055 ssl:default [Connection refused]\n2020-06-19 13:23:17 ERROR    rasa.core.processor  - Encountered an exception while running action \'action_greet_user\'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.\n2020-06-19 13:24:04 ERROR    rasa.core.actions.action  - Failed to run custom action \'action_greet_user\'. Couldn\'t connect to the server at \'http://localhost:5055/webhook\'. Is the server running? Error: Cannot connect to host localhost:5055 ssl:default [Connection refused]\n2020-06-19 13:24:04 ERROR    rasa.core.processor  - Encountered an exception while running action \'action_greet_user\'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.\n

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它不起作用。请求 Rasa 服务器作为 API 的正确方法是什么？阅读文档后，我不清楚如何正确使用 API。

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我也尝试过这个：

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在：

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import requests\n\nresponse = requests.get(\'http://localhost:5005/webhooks/rest/webhook\') \nprint(response) \nprint(response.headers) \nprint(response.content)\n

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出去：

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<Response [405]>\n{\'Connection\': \'keep-alive\', \'Keep-Alive\': \'5\', \'Allow\': \'POST\', \'Access-Control-Allow-Credentials\': \'true\', \'Content-Length\': \'60\', \'Content-Type\': \'text/plain; charset=utf-8\'}\nb\'Error: Method GET not allowed for URL /webhooks/rest/webhook\'\n

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Answer 1

我最终发现这就是你请求终点的方式：

localhost:5005/model/parse -s -d '{ "text": "hi" }'

文档应该更清晰。