将字符串截断为前n个单词

Question

将字符串截断为前n个单词的最佳方法是什么？

Answer 1

n = 3
str = "your long    long   input string or whatever"
str.split[0...n].join(' ')
 => "your long long"


str.split[0...n] # note that there are three dots, which excludes n
 => ["your", "long", "long"]

Answer 2

你可以这样做:

s     = "what's the best way to truncate a ruby string to the first n words?"
n     = 6
trunc = s[/(\S+\s+){#{n}}/].strip

如果你不介意复制.

您也可以通过调整空格检测来应用Sawa的改进(希望我仍然是数学家,这将是一个定理的一个伟大名称):

trunc = s[/(\s*\S+){#{n}}/]

如果你必须处理n的数量大于当时的单词数量,s你可以使用这个变体:

s[/(\S+(\s+)?){,#{n}}/].strip