如何将对象深度属性转换为另一个？

Question

以下是具有重复属性的深度嵌套对象。

如何转换以下深度嵌套的对象

const obj = {
    prop1: {
        properties: { value: {} },
    },
    prop2: {
        properties: { subProp: { properties: { value: {} } } },
    },
    prop3: {
        properties: { subProp: { properties: { subSubProp: { properties: { value: {} } } } } },
    },
};

进入这个：

const obj = {
    prop1: { value: {} },
    prop2: { subProp: { value: {} } },
    prop3: { subProp: { subSubProp: { value: {} } } },
};

//if properties exists, else leave as it is (in each level)

Answer 1

您可以构建新对象并检查该值是否为对象以及是否properties存在。然后使用properties或 对象进行递归调用。

const
    removeProperties = object => Object.fromEntries(Object
        .entries(object)
        .map(([key, value]) => [
            key,
            value && typeof value === 'object'
                ? removeProperties('properties' in value ? value.properties : value)
                : value
        ])
    ),
    obj = { prop1: { properties: { value: {} } }, prop2: { properties: { subProp: { properties: { value: {} } } } }, prop3: { properties: { subProp: { properties: { subSubProp: { properties: { value: {} } } } } } } };

console.log(removeProperties(obj));

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没有 Object.fromEntries

const
    removeProperties = object => Object
        .entries(object)
        .map(([key, value]) => [
            key,
            value && typeof value === 'object'
                ? removeProperties('properties' in value ? value.properties : value)
                : value
        ])
        .reduce((object, [key, value]) => ({ ...object, [key]: value }), {}),
    obj = { prop1: { properties: { value: {} } }, prop2: { properties: { subProp: { properties: { value: {} } } } }, prop3: { properties: { subProp: { properties: { subSubProp: { properties: { value: {} } } } } } } };

console.log(removeProperties(obj));

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