Abd*_*z P 7 android fragment kotlin
我收到错误消息:无法访问 'android.support.v4.app.Fragment' 这是 'com.android.youtube.player.YoutubePlayerSupportFragment' 的超类型 检查您的模块类路径或冲突的依赖项
当我在下面的代码中将我的课程带到红色下划线的函数调用initialize()时。
正畸类:AppCompatActivity(){
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_orthodontics)
val youtubefragment= supportFragmentManager.findFragmentById(R.id.fragment2) as YouTubePlayerSupportFragment
youtubefragment.initialize("AIzaSyB-5LPG4MIHD1XDb56azVDZYmTfd2o",object: YouTubePlayer.OnInitializedListener{
override fun onInitializationSuccess(p0: YouTubePlayer.Provider?,p1: YouTubePlayer?,p2: Boolean) {
if(p1==null) return
if(p2) {
p1.play()
} else {
p1.cueVideo("gh1p3TGlf8c&t=05")
p1.setPlayerStyle(YouTubePlayer.PlayerStyle.DEFAULT)
}
}
override fun onInitializationFailure(p0: YouTubePlayer.Provider?,p1: YouTubeInitializationResult?) {
TODO("Not yet implemented")
}
})
}
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}
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