我正在创建winForm应用程序,在Onbutton中单击我从两个数据库Mysql和Sqlite数据库中收集数据表.在将Linq查询转换为IEnumerable时,我将获取Casting错误,以便将查询值提取到DataTable以在DataGrid视图中显示.
private void button1_Click(object sender, EventArgs e)
{
var obj = new table1TableAdapter(); //Mysql Table Adapter
var obj2 = new Table1TableAdapter(); // Sqlite Table Adapter
var ds = new DataSet();
ds.Tables.Add(obj.GetData());
ds.Tables.Add(obj2.GetData());
var tab1 = ds.Tables[0];
var tab2 = ds.Tables[1];
var query = from o in tab1.AsEnumerable()
join od in tab2.AsEnumerable()
on o.Field<string>("Name") equals od.Field<string>("Name")
select new
{
Name = o.Field<string>("Name"),
Rollno = od.Field<Int64>("rollno"),
Book = o.Field<string>("Book")
};
var q2 = (IEnumerable<DataRow>)query; //Unable to cast object of type <JoinIterator>
DataTable orderTable = q2.CopyToDataTable();
dataGridView1.DataSource = orderTable;
}
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看看你的代码,我会说,为什么要把它投入IEnumerable<DataRow>呢?只需将查询绑定到GridView即可.
dataGridView1.DataSource = query.ToList();
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