Python Seaborn：在 Facetgrid 中绘制多个 distplot

Question

我有一个如下所示的数据框：

df：

RY         MAJ_CAT                  Value
2016    Cause Unknown              0.00227
2016    Vegetation                 0.04217
2016    Vegetation                 0.04393
2016    Vegetation                 0.07878
2016    Defective Equip            0.00137
2018    Cause Unknown              0.00484
2018    Defective Equip            0.01546
2020    Defective Equip            0.05169
2020    Defective Equip            0.00515
2020    Cause Unknown              0.00050

我想绘制给定年份值的分布。所以我使用以下代码使用了 seaborn 的 distplot：

year_2016 = df[df['RY']==2016]
year_2018 = df[df['RY']==2018]
year_2020 = df[df['RY']==2020]
sns.distplot(year_2016['value'].values, hist=False,rug=True)    
sns.distplot(year_2018['value'].values, hist=False,rug=True)   
sns.distplot(year_2020['value'].values, hist=False,rug=True)

在下一步中，我想绘制 MAJ_CAT 给定年份的相同值分布。所以我决定使用seaborn的Facetgrid，下面是代码：

g = sns.FacetGrid(df,col='MAJ_CAT')
g = g.map(sns.distplot,df[df['RY']==2016]['value'].values, hist=False,rug=True))    
g = g.map(sns.distplot,df[df['RY']==2018]['value'].values, hist=False,rug=True))    
g = g.map(sns.distplot,df[df['RY']==2020]['value'].values, hist=False,rug=True))

但是，当它运行上述命令时，它会引发以下错误：

 KeyError: "None of [Index([(0.00227, 0.04217, 0.043930000000000004, 0.07877999999999999, 0.00137, 0.0018800000000000002, 0.00202, 0.00627, 0.00101, 0.07167000000000001, 0.01965, 0.02775, 0.00298, 0.00337, 0.00088, 0.04049, 0.01957, 0.01012, 0.12065, 0.23699, 0.03639, 0.00137, 0.03244, 0.00441, 0.06748, 0.00035, 0.0066099999999999996, 0.00302, 0.015619999999999998, 0.01571, 0.0018399999999999998, 0.03425, 0.08046, 0.01695, 0.02416, 0.08975, 0.0018800000000000002, 0.14743, 0.06366000000000001, 0.04378, 0.043, 0.02997, 0.0001, 0.22799, 0.00611, 0.13960999999999998, 0.38871, 0.018430000000000002, 0.053239999999999996, 0.06702999999999999, 0.14103, 0.022719999999999997, 0.011890000000000001, 0.00186, 0.00049, 0.13947, 0.0067, 0.00503, 0.00242, 0.00137, 0.00266, 0.38638, 0.24068, 0.0165, 0.54847, 1.02545, 0.01889, 0.32750999999999997, 0.22526, 0.24516, 0.12791, 0.00063, 0.0005200000000000001, 0.00921, 0.07665, 0.00116, 0.01042, 0.27046, 0.03501, 0.03159, 0.46748999999999996, 0.022090000000000002, 2.2972799999999998, 0.69021, 0.22529000000000002, 0.00147, 0.1102, 0.03234, 0.05799, 0.11744, 0.00896, 0.09556, 0.03202, 0.01347, 0.00923, 0.0034200000000000003, 0.041530000000000004, 0.04848, 0.00062, 0.0031100000000000004, ...)], dtype='object')] are in the [columns]"

我不确定我在哪里犯了错误。有人可以帮我解决这个问题吗？

Answer 1

设置数据框

import pandas as pd
import numpy as np
import seaborn as sns

# setup dataframe of synthetic data
np.random.seed(365)
data = {'RY': np.random.choice([2016, 2018, 2020], size=400),
        'MAJ_CAT': np.random.choice(['Cause Unknown', 'Vegetation', 'Defective Equip'], size=400),
        'Value': np.random.random(size=400) }

df = pd.DataFrame(data)

更新答案

• 从 seaborn v0.11
• sns.displot与kind='kde'和一起使用rug=True
  • 是用于在 FacetGrid 上绘制分布图的图形级界面。

'MAJ_CAT'一起绘制

sns.displot(data=df, x='Value', hue='RY', kind='kde', palette='tab10', rug=True)

'MAJ_CAT'单独绘图

sns.displot(data=df, col='MAJ_CAT', x='Value', hue='RY', kind='kde', palette='tab10', rug=True)

原答案

• 在seaborn v0.11,distplot已弃用

分布图

• 合并原代码生成distplot

for year in df.RY.unique():
    values = df.Value[df.RY == year]
    sns.distplot(values, hist=False, rug=True)

分面网格

• 正确配置映射并添加hue到FacetGrid

g = sns.FacetGrid(df, col='MAJ_CAT', hue='RY')
p1 = g.map(sns.distplot, 'Value', hist=False, rug=True).add_legend()