Rup*_*esh 10 android google-maps area
我们可以在iPhone中为地图上的特定位置设置周围区域,如下所示
CLLocationCoordinate2D coord = {latitude:37.09024, longitude:-95.712891};
CLLocationDistance latitudinalMeters;
latitudinalMeters =NoOfMiles * 1609.344;
CLLocationDistance longitudinalMeters;
longitudinalMeters = NoOfMiles * 1609.344;
mapViewHome.region = MKCoordinateRegionMakeWithDistance(coord, latitudinalMeters, longitudinalMeters);
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有没有Android的等效方法?
Mac*_*ski 15
此代码不是生产质量.请在此处使用评论中的克里斯建议:https://issuetracker.google.com/issues/35823607#comment4
此问题最初是针对Maps API v1提出的.这个答案适用于v2,但可以很容易地改为v1,所以......
没有简单的方法来做到这一点.
您可能想要在gmaps-api-issues上请求此功能.
等待在Google端实施此操作可能需要几个月的时间,所以我会这样做:
private static final double ASSUMED_INIT_LATLNG_DIFF = 1.0;
private static final float ACCURACY = 0.01f;
public static LatLngBounds boundsWithCenterAndLatLngDistance(LatLng center, float latDistanceInMeters, float lngDistanceInMeters) {
latDistanceInMeters /= 2;
lngDistanceInMeters /= 2;
LatLngBounds.Builder builder = LatLngBounds.builder();
float[] distance = new float[1];
{
boolean foundMax = false;
double foundMinLngDiff = 0;
double assumedLngDiff = ASSUMED_INIT_LATLNG_DIFF;
do {
Location.distanceBetween(center.latitude, center.longitude, center.latitude, center.longitude + assumedLngDiff, distance);
float distanceDiff = distance[0] - lngDistanceInMeters;
if (distanceDiff < 0) {
if (!foundMax) {
foundMinLngDiff = assumedLngDiff;
assumedLngDiff *= 2;
} else {
double tmp = assumedLngDiff;
assumedLngDiff += (assumedLngDiff - foundMinLngDiff) / 2;
foundMinLngDiff = tmp;
}
} else {
assumedLngDiff -= (assumedLngDiff - foundMinLngDiff) / 2;
foundMax = true;
}
} while (Math.abs(distance[0] - lngDistanceInMeters) > lngDistanceInMeters * ACCURACY);
LatLng east = new LatLng(center.latitude, center.longitude + assumedLngDiff);
builder.include(east);
LatLng west = new LatLng(center.latitude, center.longitude - assumedLngDiff);
builder.include(west);
}
{
boolean foundMax = false;
double foundMinLatDiff = 0;
double assumedLatDiffNorth = ASSUMED_INIT_LATLNG_DIFF;
do {
Location.distanceBetween(center.latitude, center.longitude, center.latitude + assumedLatDiffNorth, center.longitude, distance);
float distanceDiff = distance[0] - latDistanceInMeters;
if (distanceDiff < 0) {
if (!foundMax) {
foundMinLatDiff = assumedLatDiffNorth;
assumedLatDiffNorth *= 2;
} else {
double tmp = assumedLatDiffNorth;
assumedLatDiffNorth += (assumedLatDiffNorth - foundMinLatDiff) / 2;
foundMinLatDiff = tmp;
}
} else {
assumedLatDiffNorth -= (assumedLatDiffNorth - foundMinLatDiff) / 2;
foundMax = true;
}
} while (Math.abs(distance[0] - latDistanceInMeters) > latDistanceInMeters * ACCURACY);
LatLng north = new LatLng(center.latitude + assumedLatDiffNorth, center.longitude);
builder.include(north);
}
{
boolean foundMax = false;
double foundMinLatDiff = 0;
double assumedLatDiffSouth = ASSUMED_INIT_LATLNG_DIFF;
do {
Location.distanceBetween(center.latitude, center.longitude, center.latitude - assumedLatDiffSouth, center.longitude, distance);
float distanceDiff = distance[0] - latDistanceInMeters;
if (distanceDiff < 0) {
if (!foundMax) {
foundMinLatDiff = assumedLatDiffSouth;
assumedLatDiffSouth *= 2;
} else {
double tmp = assumedLatDiffSouth;
assumedLatDiffSouth += (assumedLatDiffSouth - foundMinLatDiff) / 2;
foundMinLatDiff = tmp;
}
} else {
assumedLatDiffSouth -= (assumedLatDiffSouth - foundMinLatDiff) / 2;
foundMax = true;
}
} while (Math.abs(distance[0] - latDistanceInMeters) > latDistanceInMeters * ACCURACY);
LatLng south = new LatLng(center.latitude - assumedLatDiffSouth, center.longitude);
builder.include(south);
}
return builder.build();
}
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用法:
LatLngBounds bounds = AndroidMapsExtensionsUtils.boundsWithCenterAndLatLngDistance(new LatLng(51.0, 19.0), 1000, 2000);
map.moveCamera(CameraUpdateFactory.newLatLngBounds(bounds, 0));
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笔记:
LatLng south计算出来的第三部分并像经度那样去做:这对于latDistance的小值是准确的(猜测你不会看到100km以下的差异)| 归档时间: |
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